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Algebra Lesson 2-4 Quiz v2

Last updated about 2 years ago

6 questions

1

1

1

1

0.75

0.75

Question 1

1.

Which of the following is the equation of a line that is parallel to the graph y=-\frac{7}{4}x+5 ?

y=\frac{4}{7}x-9

y=-\frac{7}{4}x-9

y=-\frac{4}{7}x-9

y=\frac{7}{4}x-9

Question 2

2.

Which equation has a graph that is perpendicular to the graph of 3x+2y=5 ?

6x+4y=10

2x+3y=5

y-2=5(x-3)

y=\frac{2}{3}x+5

Question 3

3.

Select the equation of a line in slope-intercept form that passes through (5, -5) and is perpendicular to the graph of y=7x-\frac{3}{5} .

y=-\frac{1}{7}x+\frac{30}{7}

y=7x+\frac{30}{7}

y=7x-\frac{30}{7}

y=-\frac{1}{7}x-\frac{30}{7}

Question 4

4.

Choose the correct way to end the sentence.

The lines y-3=2(x+4) and x-2y=7 are

parallel

perpendicular

neither

Question 5

5.

The eightball (black) and cue ball (white) are shot across a pool table so that their initial paths are at right angles to each other and they collide in the middle of the table.

When a coordinate grid is superimposed onto the table, we can say that the path of the eightball (until collision) is defined by the equation y=-\frac{1}{2}x+\frac{29}{4}. If the point of collision is (\frac{15}{2},\frac{7}{2}), what equation describes the initial path of the cue ball?

y-\frac{7}{2}=-2(x+\frac{15}{2})

y-\frac{7}{2}=\frac{1}{2}(x+\frac{15}{2})

y-\frac{7}{2}=2(x-\frac{15}{2})

y+\frac{7}{2}=-\frac{1}{2}(x-\frac{15}{2})

Question 6

6.

Continuing the scenario from question #5:

Suppose the cue ball starated all the way at the side of the table that is on the bottom of the picture, corresponding to the x-axis, and traveled along the same path (red line). What would the coordinates of its starting point on the x-axis be?