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Laabri

22396

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Last updated over 7 years ago
20 Nsɛmmisa
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Asemmisa {{asɛmmisaAhyɛnsode}}
1.

Solve: 6x – 8x + 2 = –4x + 8

Asemmisa {{asɛmmisaAhyɛnsode}}
2.

For the linear equation, indicate whether the equation has no solution, one solution or infinitely many solutions.

6x + 8 = –8

Asemmisa {{asɛmmisaAhyɛnsode}}
3.

For the linear equation, indicate whether the equation has no solution, one solution or infinitely many solutions.

2x – 9 + 3x = 5x – 6 – 3

Asemmisa {{asɛmmisaAhyɛnsode}}
4.

For the linear equation, indicate whether the equation has no solution, one solution or infinitely many solutions.

2(3x + 1) = 3(2x + 1)

Asemmisa {{asɛmmisaAhyɛnsode}}
5.

Click and drag each equation into the appropriate box according to the number of solutions.

  • 5x + 14 = 3x + 14

  • 2x + 9 = 2x – 9

  • 3(2x + 2) = 2(3x + 3)

  • 8x – 4 = 2x

  • 5x – 6 = 5x + 8 – 14

  • 5x + 2 = 2x + 5

  • No Solutions

  • One Solution

  • Infinitely Many Solutions

Asemmisa {{asɛmmisaAhyɛnsode}}
6.

Solve: 4(x – 1) = x + 5

Asemmisa {{asɛmmisaAhyɛnsode}}
7.

Solve: –11x + 3 = –85

Asemmisa {{asɛmmisaAhyɛnsode}}
8.

Solve: –16 = –4(x + 1)

Asemmisa {{asɛmmisaAhyɛnsode}}
9.

Use the numbers provided to fill in each blank and create an equation that has no real solution. Each number may be used once. Type the entire right side of the equation as your answer.

1 –2 2 –4 4 5 9

5x – 2 + 4x = _______x + ________

Asemmisa {{asɛmmisaAhyɛnsode}}
10.

Use the numbers provided to fill in each blank and create an equation that has infinitely many solutions. Each number may be used once. Type the entire right side of the equation as your answer.

1 –2 2 –3 3 –4 4

x + 2x + 3 + 3 = _____(x + _____)

Asemmisa {{asɛmmisaAhyɛnsode}}
11.

Mika is solving the following equation:

3 + 5x = 5(x + 2) – 7

Her final two steps are:

3 + 5x = 5x + 3

3 = 3

Select the statement(s) that correctly interprets Mika's solution.

Asemmisa {{asɛmmisaAhyɛnsode}}
12.

Malila is solving the following equation:

3(x + 4) = 3x + 11

Her final two steps are:

3x + 12 = 3x + 11

12 = 11

Select the statement(s) that correctly interprets Malila's solution.

Asemmisa {{asɛmmisaAhyɛnsode}}
13.

Miguel is solving the following equation:

–3x – 10 – 2 = 7x – 7 – 5x

His final two steps are:

–3x = 3

x = –1

Select the statement(s) that correctly interprets Miguel's solution.

Asemmisa {{asɛmmisaAhyɛnsode}}
14.

Enter the value of x that makes the equation true. ( Solve for x )

–2(x – 1) + x = 17 + 4x

Asemmisa {{asɛmmisaAhyɛnsode}}
15.

Enter the value of x that makes the equation true. ( Solve for x )

2(4x − 3) − 8 = 4 + 2x

Asemmisa {{asɛmmisaAhyɛnsode}}
16.

Enter the value of x that makes the equation true. ( Solve for x )

11x – 9 = –x + 15

Asemmisa {{asɛmmisaAhyɛnsode}}
17.

Enter the value of x that makes the equation true. ( Solve for x )

5x + 34 = −2(1 − 7x)

Asemmisa {{asɛmmisaAhyɛnsode}}
18.

Enter the value of x that makes the equation true. ( Solve for x )

6 = 1 − 2x + 5

Asemmisa {{asɛmmisaAhyɛnsode}}
19.

Which of the following is the best first step in solving the following equation?

2(4x − 3) − 8 = 4 + 2x

Asemmisa {{asɛmmisaAhyɛnsode}}
20.

Which of the following is the best first step in solving the following equation?

8x + 16 = 11x + 2