Algebra 2 6-6 Independent Practice: Function Operations
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Last updated almost 3 years ago
9 questions
10 points
10
Question 1
1.
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Question 2
2.
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Question 3
3.
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Question 4
4.
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Question 5
5.
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Question 6
6.
50 points
50
Question 7
7.
Error Analysis: Your friend used some simple functions and found the following to be true for particular functions f and g and concluded that function composition is commutative.
Give an example to show that your friend is mistaken.
Define each of the following in your counterargument:
a specific function f(x)
a specific function g(x)
the composition of functions (f \circ g)(x)
the composition of functions (g \circ f)(x)
Note: To form a counterexample, (f \circ g)(x) should not equal (g \circ f)(x).
10 points
10
Question 8
8.
Open-Ended: List two functions f and g such that, for all real numbers x f(g(x))=x.
HINT: Consider simple functions that include inverse operations.
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