Tim has a graphics design business. He printed 45,000 business cards last year. However, 2534 business cards were printed incorrectly. Tyler also has a graphics design business. He printed 345,000 business cards last year. How many cards can Tyler make errors on and still be more accurate than Tim's business? ( include Tim's % of printing in your solution)
Try the problems #9-#14 below they are from Section 5.3. You are required to complete #15
Question 9
9.
Question 10
10.
Question 11
11.
Question 12
12.
Question 13
13.
Question 14
14.
BHS hockey team plays two games. Use a tree diagram to list possible win, loss or tie and the sequences the team can experience for the set of two games.
Question 15
15.
What additional questions do you have on 5.1-5.2 ? OR Write your own probability problem for the class to solve. Please write below.
In an election for 2020 is made up of 13 women and 15 men. One of them will be elected CEO of the company. Select all that apply.
13/28 chance that a women will become CEO
15/13 chance that a man will become CEO
53% chance that a man will become CEO
.86 chance that a women will become CEO
Two cards are drawn at random, from a standard deck. ( 52 cards, 13 hearts, 13 diamonds, 13 spades, 13 clubs) Are the outcomes of the two cards independent? Select all true statements
If the first card is replaced, the outcomes are independent
Replacing the first card restores the orginal sample space
If the first card is not replaced, the outcomes are not independent, because removing the first card changes the sample space,
If the first card is replaced, the outcomes are dependent
Two cards are drawn at random, from a standard deck. ( 52 cards, 13 hearts, 13 diamonds, 13 spades, 13 clubs) If the first card is replaced before the second one is drawn, what is the probability that both cards will be hearts?
P( heart and heart) = 13/52 * 13/52 = 0.063
P(heart and heart) = 1/52 * 1/52 =0.000369
P(heart and heart) = 1/4 * 1/4 = 1/17=0.0625
none of the above
Two cards are drawn at random, from a standard deck. ( 52 cards, 13 hearts, 13 diamonds, 13 spades, 13 clubs) If the first card is not replaced before the sencond one is drawn, what is the probability that both cards will be hearts?
P( heart and heart) = 13/52 * 12/51 = 0.059
P(heart and heart) = 4/52 * 3/51 =0.00452
P(heart and heart) = 1/13 * 1/13 = 0.00592
none of the above
Use the BGSU table above: Compute P( salary is at or above upper middle income)
291/1153
406/1153
697/1153
406/511
291/642
Use the BGSU table above: Compute P( salary is at or above upper middle income, given graduated college)
291/1153
406/1153
697/1153
406/511
291/642
The Dean at Akron University found that 23% of the male population majored in teaching. If 67% of the students at Akron are men, what is the probability that a student chosen at random will be a male student majoring in teaching?
44%
15%
100%
None of the above
There is money to send two of the eight city council members to a conference in Cleveland. All want to go, so they decide to choose the members to go by a random process. How many different combinations of two council members can be selected from the 8 who want to go to the conference?
56
28
20
7
Compute
14
21
42
48
There are 5 multiple choice questions on an exam, each with 4 possible answers. Use the multiplication rule of counting to determine the number of possible aswers sequences for the five questions. Only one of the sets can contain all five correct answers. How many possible sequences are there?
4
16
1024
2048
none of the above
There are 5 multiple choice questions on an exam, each with 4 possible answers. Use the multiplication rule of counting to determine the number of possible aswers sequences for the five questions. Only one of the sets can contain all five correct answers. If you are guessing, so that you are as likely to choose one sequence of answers as another, what is the probability of getting all five answers correc?
P( all correct) = 1/16 = 0.0625
P( all correct) = 1/ 1024= 0.00098
P( all correct) = 1/ 2048=0.000488
none of the above
A coin is tossed six times. Use the multiplication rule of counting to determine the number of possible head-tail sequences that can occur.
