10_Phys U1 Summative (45MC)

the rate of change of velocity

the change in time over velocity

the change in speed over time

the rate of change of speed

total acceleration divided by time

total velocity divided by time

total displacement divided by time

total distance divided by time

acceleration

change in displacement

change in speed

change in acceleration

change in velocity

change in acceleration

speed

velocity

acceleration

9.81 m/s^2

-9.81 ms^2

-9.81 m/s^2

9.81 ms^2

velocity, mass

speed, mass

speed, force

velocity, force

The vector addition of all the forces related to object is zero

The vector addition of the forces on the vertical is zero

The vector addition of the forces on the horizontal is zero

there is air resistance and magnitude of the mass equals the weight.

there is air resistance and magnitude of the force equals the weight.

there is air resistance and magnitude of the friction equals the weight.

Inertia

Friction in general

Static Friciton

Dynamic Friction

2nd Newton's Law

1st Newton's Law

3rd Newton's Law

Static Friction

Friction

Dynamic Friction

Normal Force

Static Friction

Friction

Normal Force

Dynamic Friction

Stopping distance is the addition of the reaction distance and braking distance.

Stopping distance is the addition of all the braking distance.

Reaction distance is the addition of the stopping distance and braking distance.

Braking distance is the addition of the reaction distance and stopping distance.

W = mg

F = mg

W = ma

F = ma

Are the same because both are measured in Newtons.

Are the same because both are measured in kilograms.

are not the same because mass is always constant.

are not the same because weight is always constant.

same direction but opposite in magnitude.

same magnitude but opposite in direction.

direction

mass

unit

initial velocity or initial speed

initial speed

initial velocity

ms^-2

m/s^-2

ms²

changing due to gravity 9.81

constant because there is no air resistance affecting the projectile.

constant because mass is constant.

changing due to acceleration of 9.81

= 28.28 x cos25.6º = 25.51 m/s

= 28.28 x sin25.6º = 12.22 m/s

= 28.28 x cos25.6º = 12.22 m/s

= 28.28 x sin25.6º = 25.51 m/s

consider v = 28.28 x sin25.6 in vertical "suvat"

consider v = zero in horizontal "suvat"

consider v = 28.28 x sin25.6 in horizontal "suvat"

consider v = zero in vertical "suvat"

The velocity is the cos of 25.6º

The velocity is the sin of 25.6º

the time is exactly what takes to reach the highest altitude.

the time is double of what takes to reach the highest altitude.

20 m/s

20 x cos90º

-20 m/s

-20 x cos90º

9.81 m/s^2

-9.81 m/s^-2

-9.81 m/s^2

9.81 m/s^-2

+400 m

+800 m

+600 m

+1,000 m

negative acceleration when velocity starts in the negative region.

positive acceleration when velocity starts in the negative region.

negative acceleration when velocity starts in the positive region.

positive acceleration when velocity starts in the positive region.

positve acceleration and positive constant velocity

no acceleration and negative constant velocity

no acceleration and positive constant velocity

positve acceleration and negative constant velocity

zero acceleration

negative acceleration

positive acceleration

This is velocity-time graph when acceleration is negative

This is displacement time graph when acceleration is negative and velocity is constant.

This is displacement time graph when acceleration is positive and velocity is constant.

This is velocity-time graph when acceleration is positive

C

B

A

C

A

B

25 m/s

50 m/s

75 m/s

100 m/s

30,000 N

300 N

3,000 N

-1000 N

900 N

1,000 N

-900 N

300

10

30

100

60

5

500

50

5 kg

50 kg

15 kg

10.5 kg

30 N

26.4 N

22 N

50.44 N

2.2 N

22 N

13 N

4.4 N

30 N

No, because impact force is smaller than maximum coefficient static friction.

No, because impact force is smaller than maximum static friction.

Yes, because impact force is greater than maximum coefficient static friction.

Yes, because impact force is greater than maximum static friction.

-10,000 N

-1,000 N

+1,000 N

+10,000 N

3,000 N

30,000 N

-30,000 N

-3,000 N

+14,000 N

-6,000 N

-14,000 N

+6,000 N

8 kg

12 kg

18 kg

2 kg