Solving for angles in the unit circle d
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Last updated over 5 years ago
8 questions
Note from the author:
Unit cirle
4
Given the trig ratio ( on the right) determine the quadrants the angles must lie in, then drag to the appropriate box on the right.
Given the trig ratio ( on the right) determine the quadrants the angles must lie in, then drag to the appropriate box on the right.
- cosx=-√2/2
- cosx = 1/2
- sinx= √3/2
- tanx=-1
- Quads I and II
- Quads I and III
- Quads II and III
- quads I and IV
- Quads II and IV
2
2cosx=1 , what are the two values for x in degrees? Check two boxes
2cosx=1 , what are the two values for x in degrees? Check two boxes
2
4sinx-2=0 , what are the two values for x in degrees? Check two boxes
4sinx-2=0 , what are the two values for x in degrees? Check two boxes
2
2sinx+√3=0 , what are the two values for x in degrees? Check two boxes
2sinx+√3=0 , what are the two values for x in degrees? Check two boxes
2
tanx=√3 , what are the two values for x in degrees? Check two boxes
tanx=√3 , what are the two values for x in degrees? Check two boxes
2
2-2tanx=4 , what are the two values for x in degrees? Check two boxes
2-2tanx=4 , what are the two values for x in degrees? Check two boxes
4
Given the trig ratios ( on the left) drag the ratio to the matching angle.
Given the trig ratios ( on the left) drag the ratio to the matching angle.
- cosx= -√2/2
- sinx=–√2/2
- tanx=1
- tanx=-1
- π/4 and 3π/4
- π/4 and 5π/4
- 3π/4 and 5π/4
- 5π/4 and 7π/4
- 3π/4 and 7π/4
4
Given the trig ratios ( on the left) drag the ratio to the angles that satisfy the equation
Given the trig ratios ( on the left) drag the ratio to the angles that satisfy the equation
- cosx= -√3/2
- 2cosx= √3
- tanx=-√3/3
- tanx=√3/3
- π/6 and 5π/6
- 5π/6 and 7π/6
- π/6 and 11π/6
- π/6 and 7π/6
- 5π/6 and 11π/6