Open Up - Grade 8 - Mathematics - Unit 7 - Lesson 8
By Formative Library
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Last updated almost 3 years ago
5 Questions
1
1.
Select all the true statements:
Select all the true statements:
8.EE.1
1
2.
Find x, y, and z if (3⋅5)^{4}⋅(2⋅3)^{5}⋅(2⋅5)^{7}=2^{x}⋅3^{y}⋅5^{z}
Find x, y, and z if (3⋅5)^{4}⋅(2⋅3)^{5}⋅(2⋅5)^{7}=2^{x}⋅3^{y}⋅5^{z}
8.EE.1
1
3.
Han found a way to compute complicated expressions more easily. Since 2⋅5=10, he looks for pairings of 2s and 5s that he knows equal 10. For example, 3⋅2^{4}⋅5^{5}=3⋅2^{4}⋅5^{4}⋅5=(3⋅5)⋅(2⋅5)^{4}=15⋅10^{4}=150,00. Use Han's technique to compute the following:
2^{4}⋅5⋅(3⋅5)^{3}
Han found a way to compute complicated expressions more easily. Since 2⋅5=10, he looks for pairings of 2s and 5s that he knows equal 10. For example, 3⋅2^{4}⋅5^{5}=3⋅2^{4}⋅5^{4}⋅5=(3⋅5)⋅(2⋅5)^{4}=15⋅10^{4}=150,00. Use Han's technique to compute the following:
2^{4}⋅5⋅(3⋅5)^{3}
8.EE.1
1
4.
Han found a way to compute complicated expressions more easily. Since 2⋅5=10, he looks for pairings of 2s and 5s that he knows equal 10. For example, 3⋅2^{4}⋅5^{5}=3⋅2^{4}⋅5^{4}⋅5=(3⋅5)⋅(2⋅5)^{4}=15⋅10^{4}=150,00. Use Han's technique to compute the following:
\frac{2^{3}⋅5^{2}⋅(2⋅3)^{2}⋅(3⋅5)^{2}}{3^{2}}
Han found a way to compute complicated expressions more easily. Since 2⋅5=10, he looks for pairings of 2s and 5s that he knows equal 10. For example, 3⋅2^{4}⋅5^{5}=3⋅2^{4}⋅5^{4}⋅5=(3⋅5)⋅(2⋅5)^{4}=15⋅10^{4}=150,00. Use Han's technique to compute the following:
\frac{2^{3}⋅5^{2}⋅(2⋅3)^{2}⋅(3⋅5)^{2}}{3^{2}}
8.EE.1
1
5.
The cost of cheese at three stores is a function of the weight of the cheese. The cheese is not prepackaged, so a customer can buy any amount of cheese.- Store A sells the cheese for dollars per pound.
- Store B sells the same cheese for dollars per pound and a customer has a coupon for $5 off the total purchase at that store.
- Store C is an online store, selling the same cheese at dollar per pound, but with a $10 delivery fee.
This graph shows the price functions for stores A, B, and C.Match Stores A, B, and C with Graphs
The cost of cheese at three stores is a function of the weight of the cheese. The cheese is not prepackaged, so a customer can buy any amount of cheese.
- Store A sells the cheese for dollars per pound.
- Store B sells the same cheese for dollars per pound and a customer has a coupon for $5 off the total purchase at that store.
- Store C is an online store, selling the same cheese at dollar per pound, but with a $10 delivery fee.
This graph shows the price functions for stores A, B, and C.
Match Stores A, B, and C with Graphs
arrow_right_alt | Store A. | |
arrow_right_alt | Store B. | |
arrow_right_alt | Store C. |
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"Source: Open Up Resouces (Download for free at openupresources.org.)"