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Illustrative Math - Algebra 2 - Unit 2 - Lesson 5

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6 questions
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Question 1
1.

What is the value of 4(x-2)(x-3)+7(x-2)(x-5)-6(x-3)(x-5) when x=5?

Question 2
2.

Question 3
3.

The graph of a polynomial f(x)=(2x-3)(x-4)(x+3) has x-intercepts at 3 x values. What are they?

Question 4
4.

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Question 5
5.

Han is multiplying 10x^{4} by 0.5x^{3} and gets 5x^{7}. He says that 0.5x^{3} is not a polynomial because 0.5 is not an integer. What is the error in Han’s thinking? Explain your reasoning.

Question 6
6.

This lesson is from Illustrative Mathematics. Algebra 2, Unit 2, Lesson 5. Internet. Available from https://curriculum.illustrativemathematics.org/HS/teachers/3/2/5/index.html ; accessed 27/July/2021.

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Which polynomial function has zeros when x=-2,\frac{3}{4},5?
f(x)=(x-2)(3x+4)(x+5)
f(x)=(x-2)(4x+3)(x+5)
f(x)=(x+2)(3x-4)(x+5)
f(x)=(x+2)(4x-3)(x-5)
Match each sequence with one of the recursive definitions. Note that only the part of the definition showing the relationship between the current term and the previous term is given so as not to give away the solutions. One of the sequences matches two recursive definitions.
b(n)=b(n-1)+0
7,3,-1,-5
a(n)=a(n-1)-4
1,-\frac{1}{2},\frac{1}{4},-\frac{1}{8}
c(n)=-\frac{1}{2}*c(n-1)
8,8,8,8
Here are two expressions whose sum is a new expression, A.
Select all the values that we can put in the box so that A is a polynomial.
0
0.5
-2
-0.5
1
-1
2