8.4.8 Practice

Last updated over 1 year ago

7 questions

8.EE.7.a

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8.4.8 Practice

Last updated over 1 year ago

7 questions

Question 1

Lin was looking at the equation 2x-32+4(3x-2462)=14x. She said, “I can tell right away there are no solutions, because on the left side, you will have 2x+12x and a bunch of constants, but you have just 14x on the right side.”

Do you agree with Lin? Explain your reasoning on your paper!

Yes, I agree that Lin is correct.

No, I disagree that Lin is correct.

8.EE.7.a

Question 2

Han was looking at the equation 6x-4+2(5x+2)=16x . He said, “I can tell right away there are no solutions, because on the left side, you will have 6x+10x and a bunch of constants, but you have just 16x on the right side.”

Do you agree with Han? Explain your reasoning on your paper!

Yes, I agree that Han is correct.

No, I disagree that Han is correct.

8.EE.7.a

Question 3

Decide whether each equation is true for all, one, or no values of x.

Draggable item		Corresponding Item
-2x+4=-3x+4		True for all value of x.
6x-4=-4+6x		True for no values of x.
4x-6=4x+3		True for one values of x.

8.EE.7.a

Question 4

Solve.

3(x-5)=6

8.EE.7.a

Question 5

Solve. (Please keep your answer as a fraction)
2(x-\frac{2}{3})=0

8.EE.7.a

Question 6

Solve. (Please keep your answer as a fraction)
4x-5=2-x

8.EE.7.a

Question 7

The points (-2,0) and (0,-6) are each on the graph of a linear equation.
Is (2,6) also on the graph of this linear equation? Explain your reasoning on your paper!

Yes, the point is on the graph.

No, the point is not on the graph.

8.EE.7.a

Question 1

Lin was looking at the equation 2x-32+4(3x-2462)=14x. She said, “I can tell right away there are no solutions, because on the left side, you will have 2x+12x and a bunch of constants, but you have just 14x on the right side.”

Do you agree with Lin? Explain your reasoning on your paper!

Yes, I agree that Lin is correct.

No, I disagree that Lin is correct.

Question 2

Han was looking at the equation 6x-4+2(5x+2)=16x . He said, “I can tell right away there are no solutions, because on the left side, you will have 6x+10x and a bunch of constants, but you have just 16x on the right side.”

Do you agree with Han? Explain your reasoning on your paper!

Yes, I agree that Han is correct.

No, I disagree that Han is correct.

Question 3

Decide whether each equation is true for all, one, or no values of x.

Draggable item		Corresponding Item
-2x+4=-3x+4		True for all value of x.
6x-4=-4+6x		True for no values of x.
4x-6=4x+3		True for one values of x.

Question 4

Solve.

3(x-5)=6

Question 5

Solve. (Please keep your answer as a fraction)
2(x-\frac{2}{3})=0

Question 6

Solve. (Please keep your answer as a fraction)
4x-5=2-x

Question 7

The points (-2,0) and (0,-6) are each on the graph of a linear equation.
Is (2,6) also on the graph of this linear equation? Explain your reasoning on your paper!

Yes, the point is on the graph.

No, the point is not on the graph.

8.4.8 Practice

8.4.8 Practice

Lin was looking at the equation 2x-32+4(3x-2462)=14x. She said, “I can tell right away there are no solutions, because on the left side, you will have 2x+12x and a bunch of constants, but you have just 14x on the right side.” Do you agree with Lin? Explain your reasoning on your paper!

Han was looking at the equation 6x-4+2(5x+2)=16x . He said, “I can tell right away there are no solutions, because on the left side, you will have 6x+10x and a bunch of constants, but you have just 16x on the right side.” Do you agree with Han? Explain your reasoning on your paper!

Decide whether each equation is true for all, one, or no values of x.

Solve.3(x-5)=6

Solve. (Please keep your answer as a fraction)2(x-\frac{2}{3})=0

Solve. (Please keep your answer as a fraction)4x-5=2-x

The points (-2,0) and (0,-6) are each on the graph of a linear equation. Is (2,6) also on the graph of this linear equation? Explain your reasoning on your paper!

Lin was looking at the equation 2x-32+4(3x-2462)=14x. She said, “I can tell right away there are no solutions, because on the left side, you will have 2x+12x and a bunch of constants, but you have just 14x on the right side.” Do you agree with Lin? Explain your reasoning on your paper!

Han was looking at the equation 6x-4+2(5x+2)=16x . He said, “I can tell right away there are no solutions, because on the left side, you will have 6x+10x and a bunch of constants, but you have just 16x on the right side.” Do you agree with Han? Explain your reasoning on your paper!

Decide whether each equation is true for all, one, or no values of x.

Solve.3(x-5)=6

Solve. (Please keep your answer as a fraction)2(x-\frac{2}{3})=0

Solve. (Please keep your answer as a fraction)4x-5=2-x

The points (-2,0) and (0,-6) are each on the graph of a linear equation. Is (2,6) also on the graph of this linear equation? Explain your reasoning on your paper!

Lin was looking at the equation 2x-32+4(3x-2462)=14x. She said, “I can tell right away there are no solutions, because on the left side, you will have 2x+12x and a bunch of constants, but you have just 14x on the right side.”

Do you agree with Lin? Explain your reasoning on your paper!

Han was looking at the equation 6x-4+2(5x+2)=16x . He said, “I can tell right away there are no solutions, because on the left side, you will have 6x+10x and a bunch of constants, but you have just 16x on the right side.”

Do you agree with Han? Explain your reasoning on your paper!

Solve.

3(x-5)=6

Solve. (Please keep your answer as a fraction)
2(x-\frac{2}{3})=0

Solve. (Please keep your answer as a fraction)
4x-5=2-x

The points (-2,0) and (0,-6) are each on the graph of a linear equation.
Is (2,6) also on the graph of this linear equation? Explain your reasoning on your paper!

Lin was looking at the equation 2x-32+4(3x-2462)=14x. She said, “I can tell right away there are no solutions, because on the left side, you will have 2x+12x and a bunch of constants, but you have just 14x on the right side.”

Do you agree with Lin? Explain your reasoning on your paper!

Han was looking at the equation 6x-4+2(5x+2)=16x . He said, “I can tell right away there are no solutions, because on the left side, you will have 6x+10x and a bunch of constants, but you have just 16x on the right side.”

Do you agree with Han? Explain your reasoning on your paper!

Solve.

3(x-5)=6

Solve. (Please keep your answer as a fraction)
2(x-\frac{2}{3})=0

Solve. (Please keep your answer as a fraction)
4x-5=2-x

The points (-2,0) and (0,-6) are each on the graph of a linear equation.
Is (2,6) also on the graph of this linear equation? Explain your reasoning on your paper!