Mole Ratio Practice Wednesday (mol-mol)
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Last updated about 5 years ago
6 questions
Note from the author:
Mole Ratio practice problems
1
2SO2 + O2 -> 2SO2
Use dimensional analysis, or other method, to calculate how many moles of SO2 will be produced if 7.3 moles of O2 are reacted.
2SO2 + O2 -> 2SO2
Use dimensional analysis, or other method, to calculate how many moles of SO2 will be produced if 7.3 moles of O2 are reacted.
1
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
Use dimensional analysis, or other method, to calculate how many moles of water are produced when 77 moles of oxygen gas are reacted
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
Use dimensional analysis, or other method, to calculate how many moles of water are produced when 77 moles of oxygen gas are reacted
1
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
Use dimensional analysis, or other method, to calculate how many moles of C4H10 you need to react with 55.5 moles of oxygen gas.
2 C4H10 + 13 O2 → 8 CO2 + 10 H2O
Use dimensional analysis, or other method, to calculate how many moles of C4H10 you need to react with 55.5 moles of oxygen gas.
1
NH3+ 5O2 → 4NO + 6H2O
Use dimensional analysis, or other method, to calculate how many moles of water are produced if 7 moles of oxygen gas are reacted.
NH3+ 5O2 → 4NO + 6H2O
Use dimensional analysis, or other method, to calculate how many moles of water are produced if 7 moles of oxygen gas are reacted.
1
NH3+ 5O2 → 4NO + 6H2O
Use dimensional analysis, or other method, to calculate how many moles of nitrogen monoxide are produced if 13 moles of oxygen gas are reacted.
NH3+ 5O2 → 4NO + 6H2O
Use dimensional analysis, or other method, to calculate how many moles of nitrogen monoxide are produced if 13 moles of oxygen gas are reacted.
1
NH3+ 5O2 → 4NO + 6H2O
Use dimensional analysis, or other method, to calculate how many moles of nitrogen monoxide are produced if 21.5 moles of water were produced.
NH3+ 5O2 → 4NO + 6H2O
Use dimensional analysis, or other method, to calculate how many moles of nitrogen monoxide are produced if 21.5 moles of water were produced.