04 Solving a System Using Substitution.
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Last updated over 4 years ago
17 questions
1
y = 2x + 5
3x + y = 10
y = 2x + 5
3x + y = 10
1
x = 3y + 2
2x - 5y = 2
x = 3y + 2
2x - 5y = 2
1
3x + y = -7
-2x + 4y = 0
3x + y = -7
-2x + 4y = 0
1
x + y = 0
x - 2y = 6
x + y = 0
x - 2y = 6
1
7x + 5y = -3
y = 9x - 11
7x + 5y = -3
y = 9x - 11
1
5x + 2y = 9
x = -y - 3
5x + 2y = 9
x = -y - 3
1
y = 3x + 8
8x + 4y = 12
y = 3x + 8
8x + 4y = 12
1
y = 2x + 1
3x + 4y = 26
y = 2x + 1
3x + 4y = 26
1
20x - 30y = -50
x + 2y = 1
20x - 30y = -50
x + 2y = 1
1
2x + 5y = 44
y = 6x - 4
2x + 5y = 44
y = 6x - 4
1
y = 4x - 3
3x + 2y = 38
y = 4x - 3
3x + 2y = 38
1
10x + 3y = 19
y = 2x + 5
10x + 3y = 19
y = 2x + 5
1
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1
Please upload pictures of your work if you did not show work in the spaces provided.
Please upload pictures of your work if you did not show work in the spaces provided.
1
Please upload pictures of your work if you did not show work in the spaces provided.
Please upload pictures of your work if you did not show work in the spaces provided.
1
Please upload pictures of your work if you did not show work in the spaces provided.
Please upload pictures of your work if you did not show work in the spaces provided.
1
Please upload pictures of your work if you did not show work in the spaces provided.
Please upload pictures of your work if you did not show work in the spaces provided.