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113: Operations on Radicals - Rationalize Binomial
By Marjorie Brewer
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Bell Assignment: multiply
Question 1
1.
(2-3\sqrt{6})(-5-\sqrt{6})
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Question 2
2.
(5+\sqrt{7})(5-\sqrt{7})
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Notes L6-5c: Rationalize Binomial Denominators
note: (a+b)(a-b) are called
conjugates
. Like
[2]
, when conjugates are multipled together, the middle terms cancel.
Since we are working with square roots, we can use conjugates to eliminate the root.
Question 3
3.
Which is the conjugate of 9-\sqrt{5}?
\sqrt{5}-9
9-\sqrt{5}
9+\sqrt{5}
Question 4
4.
Multiply together 9-\sqrt{5} and its conjugate.
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Question 5
5.
Which is the conjugate of -3+\sqrt{11}?
\sqrt{11}-3
\sqrt{11}+3
-3-\sqrt{11}
-3+\sqrt{11}
Question 6
6.
Multiply together -3+\sqrt{11} and its conjugate.
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Mathematicians do not like radicals in denominators. So, we rationalize by multiplying by the conjugate.
Question 7
7.
To rationalize \LARGE \frac{-2}{-8+\sqrt{6}}
you would:
Show that you are multipling by the conjugate (on the top and bottom).
Simplify both the numerator and denominator.
Distibute (by foiling) in both the top and bottom.
Find the conjugate.
Reduce if possible.
Question 8
8.
To rationalize \LARGE \frac{-2}{-8+\sqrt{6}}
Which step is correct?
\LARGE \frac{-2 (-8+\sqrt{6})}{(-8+\sqrt{6})(-8+\sqrt{6})}
\LARGE \frac{-2 (-8-\sqrt{6})}{(-8+\sqrt{6})(-8-\sqrt{6})}
\LARGE \frac{-2 (-8+\sqrt{6})}{(-8+\sqrt{6})(-8-\sqrt{6})}
\LARGE \frac{-2 (-8-\sqrt{6})}{(-8+\sqrt{6})(-8+\sqrt{6})}
Question 9
9.
Rationalize: \LARGE \frac{-2}{-8+\sqrt{6}}
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Question 10
10.
Rationalize: \LARGE \frac{-1}{-2-\sqrt{7}}
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Question 11
11.
Rationalize: \LARGE \frac{6}{-8-\sqrt{11}}
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Question 12
12.
Rationalize: \LARGE \frac{-2}{-4+\sqrt{14}}
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Question 13
13.
Choose all that are true
I am confident in this lesson.
I would like some assistance.
I can find the conjugate.
I can rationalize binomial denominators.
Finish first 14 sections of DelatMath.