Solve (from yesterday)

(\frac{1}{262144})^{-x-8}=64^{2x-12}

hint: the base is 8

The first step in solving a basic logarithmic equation is to use the base on both sides of the problem.

Put the steps in order to solve: \log_8(x)=2

1. 8^{\log_8(x)}=8^2
2. x=64
3. \log_8(x)=2

Put the steps in order to solve: \log_x(81)=\frac{4}{3}

1. \log_x(81)=\frac{4}{3}
2. 81=x^\frac{4}{3}
3. x=27
4. 81^\frac{3}{4}=(x^\frac{4}{3})^{\frac{3}{4}}
5. x^{\log_x(81)}=x^\frac{4}{3}

Solve: \log_{10}{x}=2

Solve \log_{x}{5}=\frac{1}{4}

Solve: \log_{x}{256}=4

Solve \log_{2}{256}=x

Solve: \log_{16}{x}=\frac{1}{2}

What is the first step when solving a basic logarithmic equation?

Choose all that are true