149: Rational Equations (lvl 1&2)

Bell:

1

Solve: \frac{x-1}{x-5}=\frac{5}{7}

Notes: Rational Equations
Goals
to find the common denominator
to find the domain (what x cannot equal)
solve the problem; rejecting answers that are not in the domain

1

\frac{x}{x-3}-3=-\frac{9}{x-3}

1

1-\frac{7x}{x-1}=-\frac{7}{x-1}

1

x+\frac{2x+5}{x+6}=2

1

x+\frac{2x+5}{x-5}=\frac{3x}{x-5}

1

x-\frac{3}{x+1}=\frac{3x}{x+1}

1

2x-\frac{3}{x+2}=x

0

149: Rational Equations (lvl 1&2)

Bell:

Solve: \frac{x-1}{x-5}=\frac{5}{7}

Notes: Rational Equations

\frac{x}{x-3}-3=-\frac{9}{x-3}

1-\frac{7x}{x-1}=-\frac{7}{x-1}

x+\frac{2x+5}{x+6}=2

x+\frac{2x+5}{x-5}=\frac{3x}{x-5}

x-\frac{3}{x+1}=\frac{3x}{x+1}

2x-\frac{3}{x+2}=x

Choose all that are true

Bell:

Solve: \frac{x-1}{x-5}=\frac{5}{7}

Notes: Rational Equations

\frac{x}{x-3}-3=-\frac{9}{x-3}

1-\frac{7x}{x-1}=-\frac{7}{x-1}

x+\frac{2x+5}{x+6}=2

x+\frac{2x+5}{x-5}=\frac{3x}{x-5}

x-\frac{3}{x+1}=\frac{3x}{x+1}

2x-\frac{3}{x+2}=x

Choose all that are true