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07 - Factoring Completely Day 2
By Jeanmarie Mullen
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Last updated almost 5 years ago
18 questions
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Factor Completely
Question 1
1.
Factor Completely:
visibility
View drawing
Question 2
2.
Factor completely:
visibility
View drawing
Question 3
3.
Factor completely:
visibility
View drawing
Question 4
4.
Factor completely:
visibility
View drawing
Question 5
5.
Factor completely:
visibility
View drawing
Question 6
6.
Factor completely:
visibility
View drawing
Question 7
7.
Factor completely:
visibility
View drawing
Question 8
8.
Factor completely:
visibility
View drawing
Question 9
9.
Factor completely:
visibility
View drawing
Question 10
10.
Factor completely:
visibility
View drawing
Question 11
11.
Factor completely:
visibility
View drawing
Question 12
12.
visibility
View drawing
Question 13
13.
Question 14
14.
Question 15
15.
Question 16
16.
Question 17
17.
Question 18
18.
(n - 9)
n
(n + 5)
(n - 5)
(a + 5)
( a + 3)
a
(a - 3)
If (x - 13) is one factor of x
2
- 9x - 52, the other factor is
(x + 4)
(x + 5)
(x - 4)
(x - 39)
Expressed in factored form, the binomial 2x
2
y - 4xy
3
is equivalent to
2xy(x - 2y)
2xy(x - 2y
2
)
2xy(xy - 4y)
2x
2
y
3
(y - 2)
If one factor of 56x
4
y
3
- 42x
2
y
6
is 14x
2
y
3
, what is the other factor?
4x
2
- 3y
3
4x
2
- 3y
2
4x
2
y - 3xy
3
4x
2
y - 3xy
2
The trimonial x
2
- 14x + 49 can be expressed as
(x - 7)
2
( x +7)
2
(x - 7)(x + 2)
(x - 7)( x + 7)
Four expressions are shown below.
I 2(2x
2
- 2x - 60)
II 4(x
2
- x - 30)
III 4(x + 6)(x - 5)
IV 4x(x - 1) - 120
The expression 4x
2
- 4x - 120 is equivalent to
I and II, only
II and IV, only
I, II, and IV
II, III, and IV