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136 Logartihmic Equations

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Last updated about 5 years ago
11 questions
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Bell:

Question 1
1.

Solve (from yesterday)
(\frac{1}{262144})^{-x-8}=64^{2x-12}

hint: the base is 8

Notes L7-4

Solving Logarithmic Equations

Question 2
2.

Question 3
3.

Question 4
4.

Question 5
5.

Solve: \log_{10}{x}=2

Question 6
6.

Solve \log_{x}{5}=\frac{1}{4}

Question 7
7.

Solve: \log_{x}{256}=4

Question 8
8.

Solve \log_{2}{256}=x

Question 9
9.

Solve: \log_{16}{x}=\frac{1}{2}

Question 10
10.

What is the first step when solving a basic logarithmic equation?

Question 11
11.

Don't forget DeltaMath: Ch7: Solving Equations/Inequalities
You can now do the first four sections.
The first step in solving a basic logarithmic equation is to use the base on both sides of the problem.
True
False
Put the steps in order to solve: \log_8(x)=2
8^{\log_8(x)}=8^2
x=64
\log_8(x)=2
Put the steps in order to solve: \log_x(81)=\frac{4}{3}
\log_x(81)=\frac{4}{3}
81^\frac{3}{4}=(x^\frac{4}{3})^{\frac{3}{4}}
x^{\log_x(81)}=x^\frac{4}{3}
81=x^\frac{4}{3}
x=27
Choose all that are true
I am confident in this lesson.
I would like some assistance.
I can solve for the base: \log_{x}{64}=2
I can solve for the arguement:\log_{8}{x}=2
I can evaluate the logartithm: \log_{8}{64}=x