141 Solve LN equations
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Last updated over 4 years ago
10 questions
1
Khloe is going to invest $7,100 and leave it in an account for 9 years. Assuming the interest is compounded continuously, what interest rate, to the nearest hundredth of a percent, would be required in order for Khloe to end up with $12,600?
Use y=a(e)^{rt}
Khloe is going to invest $7,100 and leave it in an account for 9 years. Assuming the interest is compounded continuously, what interest rate, to the nearest hundredth of a percent, would be required in order for Khloe to end up with $12,600?
Use y=a(e)^{rt}
1
2\ln(2x+4)+10=4
2\ln(2x+4)+10=4
1
4\ln(7x+4)+1=13
4\ln(7x+4)+1=13
1
4\ln(7x+4)+1=13
4\ln(7x+4)+1=13
1
\log_{3}{(2x^{2}+7)}-\log_{3}{(3x+6)}=1
\log_{3}{(2x^{2}+7)}-\log_{3}{(3x+6)}=1
1
\log_{2}{(x^{2}-6)}-\log_{2}{(3x+5)}=1
\log_{2}{(x^{2}-6)}-\log_{2}{(3x+5)}=1
1
\log_{3}{(x-2)}+\log_{3}{(x+4)}=3
\log_{3}{(x-2)}+\log_{3}{(x+4)}=3
1
\log_{6}{(3x+5)}+\log_{6}{(3x-4)}=2
\log_{6}{(3x+5)}+\log_{6}{(3x-4)}=2
1
\log_{2}{(3x^{2}-2)}-\log_{2}{(4x+5)}=0
\log_{2}{(3x^{2}-2)}-\log_{2}{(4x+5)}=0
0
Choose all that are true
Choose all that are true