DelatMath was due last night. It is still open for late credit.
Without the use of a calculator, solve for x:
Solve for x:
\log_{x}{128} =7
\log_{343}{x} = \frac{1}{3}
\log_{7}{x}<2
\log_{3}{(3x+12)}>\log_{3}{(2x+6)}
Simplify
\log_{4}{9} - \log_{4}{3}
3\log_{8}{3}+\log_{8}{4}
\log_{4}{6x}+2\log_{4}{9}=1
Solve for x, round to the nearest hundredth
Solve for x, round to the nearest tenth
Solve for the exact value of x
Solve for all values of x
\log_{5}{(3x^{2}-3)}-\log_{5}{(x+5)}=1