Mixed Gas Laws Practice 2

Last updated about 5 years ago

6 Nsɛmmisa

Hyɛ no nsow a efi ɔkyerɛwfo no hɔ:

A collection of 6 gas law problems with answers to several different significant Figures. Show Your Work area has boxes for plugging numbers into the equation, simplifying/cross multiplying, and wrapping up.

For these questions, make sure your answer is in the units requested, but DON'T type your units into the answer box or it won't be recognized.

SC.912.P.12.10

Mixed Gas Laws Practice 2

Last updated about 5 years ago

6 Nsɛmmisa

Hyɛ no nsow a efi ɔkyerɛwfo no hɔ:

For these questions, make sure your answer is in the units requested, but DON'T type your units into the answer box or it won't be recognized.

P1: 9.0302 atm
P2: 1.552 atm
V2: 45.389 L
Wanted: liters of gas

SC.912.P.12.10

P: 436.49 kPa
V: 8082.7 cm³ (Convert to L, use google)
T: -56.14 °C
Wanted: moles of gas
(make sure to use the right version of R)

SC.912.P.12.10

P1: 5.0185 atm P2: 2.9035 atm T2: 165 °C Wanted: Kelvin Temperature

SC.912.P.12.10

P1: 2.4839 atm P2: 0.5694 atm V1: 1785.2 mL V2: 9294.3 mL T1: 642.97 K Wanted: Kelvin Temperature

SC.912.P.12.10

The temperature of a sample of gas is changed, causing a change in volume from 6838.3 cm³ to 2517.3 cm³. If the starting temperature was 102.85 °C, what is the final temperature in Kelvin?

SC.912.P.12.10

5.9159 mol of NH₃ is held at 7.9945 atm and -210.7 °C. What is the volume of its container in liters?

SC.912.P.12.10

Mixed Gas Laws Practice 2

Mixed Gas Laws Practice 2

P1: 9.0302 atmP2: 1.552 atmV2: 45.389 LWanted: liters of gas

P: 436.49 kPaV: 8082.7 cm3 (Convert to L, use google)T: -56.14 °CWanted: moles of gas(make sure to use the right version of R)

P1: 5.0185 atm P2: 2.9035 atm T2: 165 °C Wanted: Kelvin Temperature

P1: 2.4839 atm P2: 0.5694 atm V1: 1785.2 mL V2: 9294.3 mL T1: 642.97 K Wanted: Kelvin Temperature

The temperature of a sample of gas is changed, causing a change in volume from 6838.3 cm3 to 2517.3 cm3. If the starting temperature was 102.85 °C, what is the final temperature in Kelvin?

5.9159 mol of NH3 is held at 7.9945 atm and -210.7 °C. What is the volume of its container in liters?

P1: 9.0302 atmP2: 1.552 atmV2: 45.389 LWanted: liters of gas

P: 436.49 kPaV: 8082.7 cm3 (Convert to L, use google)T: -56.14 °CWanted: moles of gas(make sure to use the right version of R)

P1: 5.0185 atm P2: 2.9035 atm T2: 165 °C Wanted: Kelvin Temperature

P1: 2.4839 atm P2: 0.5694 atm V1: 1785.2 mL V2: 9294.3 mL T1: 642.97 K Wanted: Kelvin Temperature

The temperature of a sample of gas is changed, causing a change in volume from 6838.3 cm3 to 2517.3 cm3. If the starting temperature was 102.85 °C, what is the final temperature in Kelvin?

5.9159 mol of NH3 is held at 7.9945 atm and -210.7 °C. What is the volume of its container in liters?

P1: 9.0302 atm
P2: 1.552 atm
V2: 45.389 L
Wanted: liters of gas

P: 436.49 kPa
V: 8082.7 cm³ (Convert to L, use google)
T: -56.14 °C
Wanted: moles of gas
(make sure to use the right version of R)

The temperature of a sample of gas is changed, causing a change in volume from 6838.3 cm³ to 2517.3 cm³. If the starting temperature was 102.85 °C, what is the final temperature in Kelvin?

5.9159 mol of NH₃ is held at 7.9945 atm and -210.7 °C. What is the volume of its container in liters?

P1: 9.0302 atm
P2: 1.552 atm
V2: 45.389 L
Wanted: liters of gas

P: 436.49 kPa
V: 8082.7 cm³ (Convert to L, use google)
T: -56.14 °C
Wanted: moles of gas
(make sure to use the right version of R)

The temperature of a sample of gas is changed, causing a change in volume from 6838.3 cm³ to 2517.3 cm³. If the starting temperature was 102.85 °C, what is the final temperature in Kelvin?

5.9159 mol of NH₃ is held at 7.9945 atm and -210.7 °C. What is the volume of its container in liters?