158 more recursion

Bell:

1

Find the next term: 3, 15, 27, ...

1

If a_6=15, and
a_n=3a_{n-1}+2
Find a_8.

Recursive Sequences, level 3

1

a_1 =1
a_n=n\cdot a_{n-1}+5

Find the first 4 terms.

1

a_1 =4
a_n=(a_{n-1})^2 +n

Find the first 3 terms.

1

a_1 =6
a_n=n\cdot a_{n-1} +5

Find the first 4 terms.

1

How is the following problem different than what we have been doing? How is it the same?

a_1=7
a_{n+1}=(a_n)^2-1

1

Find the first 4 terms of [6].

1

a_1=4
a_{n+1}=4a_n-5

Find the first 4 terms.

Continue to work on DeltaMath (it is due Wednesday night).

158 more recursion

Bell:

Find the next term: 3, 15, 27, ...

If a_6=15, anda_n=3a_{n-1}+2Find a_8.

Recursive Sequences, level 3

a_1 =1a_n=n\cdot a_{n-1}+5Find the first 4 terms.

a_1 =4a_n=(a_{n-1})^2 +nFind the first 3 terms.

a_1 =6a_n=n\cdot a_{n-1} +5Find the first 4 terms.

How is the following problem different than what we have been doing? How is it the same?a_1=7a_{n+1}=(a_n)^2-1

Find the first 4 terms of [6].

a_1=4a_{n+1}=4a_n-5Find the first 4 terms.

Bell:

Find the next term: 3, 15, 27, ...

If a_6=15, anda_n=3a_{n-1}+2Find a_8.

Recursive Sequences, level 3

a_1 =1a_n=n\cdot a_{n-1}+5Find the first 4 terms.

a_1 =4a_n=(a_{n-1})^2 +nFind the first 3 terms.

a_1 =6a_n=n\cdot a_{n-1} +5Find the first 4 terms.

How is the following problem different than what we have been doing? How is it the same?a_1=7a_{n+1}=(a_n)^2-1

Find the first 4 terms of [6].

a_1=4a_{n+1}=4a_n-5Find the first 4 terms.

If a_6=15, and
a_n=3a_{n-1}+2
Find a_8.

a_1 =1
a_n=n\cdot a_{n-1}+5

Find the first 4 terms.

a_1 =4
a_n=(a_{n-1})^2 +n

Find the first 3 terms.

a_1 =6
a_n=n\cdot a_{n-1} +5

Find the first 4 terms.

How is the following problem different than what we have been doing? How is it the same?

a_1=7
a_{n+1}=(a_n)^2-1

a_1=4
a_{n+1}=4a_n-5

Find the first 4 terms.

If a_6=15, and
a_n=3a_{n-1}+2
Find a_8.

a_1 =1
a_n=n\cdot a_{n-1}+5

Find the first 4 terms.

a_1 =4
a_n=(a_{n-1})^2 +n

Find the first 3 terms.

a_1 =6
a_n=n\cdot a_{n-1} +5

Find the first 4 terms.

How is the following problem different than what we have been doing? How is it the same?

a_1=7
a_{n+1}=(a_n)^2-1

a_1=4
a_{n+1}=4a_n-5

Find the first 4 terms.