Continue to work on DeltaMath (it is due Wednesday night).
Find the next term: 3, 15, 27, ...
If a_6=15, and
a_n=3a_{n-1}+2
Find a_8.
a_1 =1
a_n=n\cdot a_{n-1}+5
Find the first 4 terms.
a_1 =4
a_n=(a_{n-1})^2 +n
Find the first 3 terms.
a_1 =6
a_n=n\cdot a_{n-1} +5
How is the following problem different than what we have been doing? How is it the same?
a_1=7
a_{n+1}=(a_n)^2-1
Find the first 4 terms of [6].
a_1=4
a_{n+1}=4a_n-5