Illustrative Math - Algebra 2 - Unit 2 - Lesson 15

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Illustrative Math - Algebra 2 - Unit 2 - Lesson 15

Posljednje ažuriranje over 3 years ago

For the polynomial function f(x)=x^{3}-2x^{2}-5x+6, we have f(0)=6,f(2)=-4,f(-2)=0,(3)=0,f(-1)=8,f(1)=0. Rewrite f(x) as a product of linear factors.

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Select all the polynomials that have (x-4) as a factor.

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Write a polynomial function,p(x) , with degree 3 that has p(7)=0.

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Which polynomial function has zeros when x=5,\frac{2}{3},-7?

f(x)=(x+5)(2x+3)(x-7)

f(x)=(x+5)(3x+2)(x-7)

f(x)=(x-5)(3x-2)(x+7)

f(x)=(x-5)(2x-3)(x+7)

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The polynomial function q(x)=3x^{4}+8x^{3}-13x^{2}-22x+24 has known factors (x+3) and (x+2). Rewrite q(x) as the product of linear factors.

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We know these things about a polynomial function f(x): it has degree 3, the leading coefficient is negative, and it has zeros at x=-5,-1,3. Sketch a graph of f(x) given this information.

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This lesson is from Illustrative Mathematics. Algebra 2, Unit 2, Lesson 15. Internet. Available from https://curriculum.illustrativemathematics.org/HS/teachers/3/2/15/index.html ; accessed 27/July/2021.

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