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Math 2 Unit 3 Test - Solving Quadratics

Last updated 6 months ago

20 Nsɛmmisa

Hyɛ no nsow a efi ɔkyerɛwfo no hɔ:

SRMHS Math 2 Unit 3 Test - Solving Quadratics (Fall 2021)

5

A.REI.4.b

NC.M2.A-REI.1

5

NC.M1.A-REI.10

NC.M2.A-REI.4.b

5

NC.M2.A-REI.4.b

5

NC.M1.A-APR.3

NC.M1.A-REI.4

NC.M1.A-SSE.3

5

NC.M2.A-REI.1

5

NC.M2.A-REI.1

5

A.SSE.3.a

NC.M1.A-APR.3

NC.M1.A-SSE.3

5

NC.M1.A-SSE.3

NC.M2.A-APR.1

5

NC.M1.A-SSE.3

NC.M2.A-APR.1

5

A.REI.4.b

NC.M2.F-IF.8

5

A.REI.4.b

NC.M2.F-IF.8

NC.M2.N-RN.2

5

NC.M2.N-RN.2

5

NC.M2.N-CN.1

5

NC.M1.A-SSE.3

5

NC.M1.A-REI.4

5

NC.M2.A-APR.1

NC.M2.A-SSE.1.a

5

NC.M2.A-APR.1

5

NC.M1.A-REI.10

5

NC.M2.A-SSE.3

5

NC.M1.A-SSE.3

NC.M2.A-SSE.1.a

Showing your work!

For any problems that say "show your work," you may choose to do one of the following:

1) Use the "show your work" area to write, draw, or type the math. (There is a math keyboard there.)

2) Do your work on notebook paper (labeled neatly) and give it to me at the end of the test.

Asemmisa {{asɛmmisaAhyɛnsode}}

1.

Solve the quadratic using any method.
x^{2}+15x+56=0
Show your work.

x=8, 7

x=-8, 7

x=8, -7

x=-8, -7

Asemmisa {{asɛmmisaAhyɛnsode}}

2.

How many real solutions does this quadratic equation have? (You do NOT need to find the solutions.)
x^{2}+9x-8=0

2 real solutions

1 real solution

no real solutions

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3.

All quadratic equations will have at least one imaginary solution.

Nokorɛ

Ɛnyɛ ampa

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4.

Solve the following quadratic equation by factoring:
6x^{2}-42x+72=0
Type your two answers in the format: _,_
(Separate your answers with a comma. Do not put any spaces. Do not type x=.)

Asemmisa {{asɛmmisaAhyɛnsode}}

5.

What would be the first step to solving the following quadratic by the Quadratic Formula?
b^{2}-16b+64=19

Add 19 to both sides of the equation.

Divide both sides of the equation by 19.

Enter the equation (as-is) into the y= on the calculator.

Subtract 19 from both sides of the equation.

Asemmisa {{asɛmmisaAhyɛnsode}}

6.

What is the solution of the quadratic equation 2x^{2} - x = 14?
Show your work in the space provided.

\frac{-1\pm\sqrt{111}}{2}

\frac{-1\pm\sqrt{113}}{4}

\frac{1\pm\sqrt{113}}{4}

\frac{1\pm\sqrt{111}}{4}

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7.

Solve for c by factoring.
Type your two answers in the format: _,_
(Separate your answers with a comma. Do not put any spaces. Do not type x=.)

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8.

Given the standard form, find the factored form.

(x+6)(x-7)

(x+6)(x+7)

(x-6)(x-7)

(x-6)(x+7)

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9.

Factor the polynomial:

(x + 5) (x + 2)

(3x + 1) (x + 2)

(x + 3) (x + 2)

(3x + 2) (x + 1)

Asemmisa {{asɛmmisaAhyɛnsode}}

10.

Solve by completing the square. Show your work. Hint: Take out a GCF first.

{ -2 , 6 }

{ -6 , -2 }

{ -6 , 2 }

{ 2 , 6 }

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11.

Solve the equation by completing the square. Simplify your answer. Use the keypad to the right of the answer blank to type the plus/minus and the square root symbols. Make sure your correct answer is on your work as well.

Asemmisa {{asɛmmisaAhyɛnsode}}

12.

Write the expression below in simplest radical form:

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13.

Simplify the radical.
\sqrt{-27}

-3i\sqrt{3}

9i\sqrt{3}

3i\sqrt{3}

-3\sqrt{3}

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14.

Factor the expression (x^{2}-81)

x(x-9)

9x(x-9)

(x-9)^2

(x+9)(x-9)

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15.

Solve the equation by using square roots. 3x^{2}=21

x=7,-7

x=\pm \sqrt{7}

x=\pm \frac{\sqrt{21}}{3}

x=-\sqrt{7},\sqrt{21}

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16.

Factor out the GCF. 6x^{5}+8x^{3}

2(3x^{5}+4x^{3})

2x(3x^{4}+4x^{2})

2x^{3}(3x^{2}+4)

6x^{3}(x^{2}+2)

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17.

Factor completely. Write your final answer without spaces! Show your work!

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18.

Solve the equation by graphing on this graphing calculator. Type your solutions in the "show your work" area for full credit. (Just having the correct graph WITHOUT identifying the solutions will NOT be full credit.)
y=4x^{2}+3x-1

Yɛayi Graphing asɛmmisa type foforo a wɔatu mpɔn adi! Asuafo rentumi mmua saa asɛmmisa yi bio.

Asemmisa {{asɛmmisaAhyɛnsode}}

19.

Choose the number that fills in the blank to complete the square.
x^{2}+12x+____

144

36

12

6

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20.

Identify the factors, and solution(s) of the quadratic equation.
Hint: You should only use four things (two for factors and two for solutions

x = -3
(x - 1)
no solution
x = ½
(2x - 1)
x = 1
(x + 3)

Factors
Solution(s)