Match the vocabulary terms with their definitions.
| Stavka koja se može prevući | arrow_right_alt | Odgovarajuća stavka |
|---|---|---|
a process that takes (usually two) terms and produces a result; common ones include addition, subtraction, multiplication, and division | arrow_right_alt | term |
an operation that assigns an output to each input | arrow_right_alt | expression |
two expressions joined by an inequality sign | arrow_right_alt | operation |
a group of terms joined by operations, a mathematical phrase | arrow_right_alt | inequality |
the smallest mathematical unit, usually a number, a variable, or a product of numbers and variables | arrow_right_alt | function |
Match the functions/operations with their inverses.
| Stavka koja se može prevući | arrow_right_alt | Odgovarajuća stavka |
|---|---|---|
f(x) = x/2 | arrow_right_alt | subtraction |
f(x) = x - 2 | arrow_right_alt | division |
addition | arrow_right_alt | f-1(x) = x + 2 |
multiplication | arrow_right_alt | f-1(x) = 2x |
Evaluate the expression for x = 5.
Enter your answer as a number.
Evaluate the expression for x = 5, y = -2
Enter your answer as a number.
If
Enter your answer as a number, no spaces.
If
Enter your answer as a number, no spaces.
Put the steps in order to evaluate the expression below.
add
perform the exponent
divide
subtract
Put the steps in order to evaluate the expression below
multiply by 1/3
perform the absolute value
subtract 22
add
perform the exponent
Solve the equation.
Enter your answer as a number, no spaces.
Solve the equation.
Enter your answer as a number, no spaces.
Solve the equation.
Enter your answer as a number, no spaces.
Solve the equation. Check for extraneous solutions.
Use x={#, #} format, with exactly one space after the comma. List the smaller number first. If there is only one solution, use x={#} format. If there are no solutions, type "no solution" with no quote marks.
Solve the equation. Check for extraneous solutions.
Use x={#, #} format, with exactly one space after the comma. List the smaller number first. If there is only one solution, use x={#} format. If there are no solutions, type "no solution" with no quote marks.
Solve the equation. Check for extraneous solutions.
Use x={#, #} format, with exactly one space after the comma. List the smaller number first. If there is only one solution, use x={#} format. If there are no solutions, type "no solution" with no quote marks.
Dr. Demo solved the equation |x+2| = 2x+7 and got x={-5, -3}.
Is his solution correct? Why or why not?