Match the vocabulary terms with their definitions.
| Stavka koja se može prevući | arrow_right_alt | Odgovarajuća stavka |
|---|---|---|
a process that takes (usually two) terms and produces a result; common ones include addition, subtraction, multiplication, and division | arrow_right_alt | term |
an operation that assigns an output to each input | arrow_right_alt | expression |
two expressions joined by an inequality sign | arrow_right_alt | operation |
a group of terms joined by operations, a mathematical phrase | arrow_right_alt | inequality |
the smallest mathematical unit, usually a number, a variable, or a product of numbers and variables | arrow_right_alt | function |
Match the functions/operations with their inverses.
| Stavka koja se može prevući | arrow_right_alt | Odgovarajuća stavka |
|---|---|---|
f(x) = x/2 | arrow_right_alt | subtraction |
f(x) = x - 2 | arrow_right_alt | division |
addition | arrow_right_alt | f-1(x) = x + 2 |
multiplication | arrow_right_alt | f-1(x) = 2x |
Evaluate the expression for x = 5.
Enter your answer as a number.
Evaluate the expression for x = 5, y = -2
Enter your answer as a number.
If
Enter your answer as a number, no spaces.
If
Enter your answer as a number, no spaces.
Put the steps in order to evaluate the expression below.
perform the exponent
divide
add
subtract
Put the steps in order to evaluate the expression below
subtract 22
perform the absolute value
multiply by 1/3
perform the exponent
add
Solve the equation.
Enter your answer as a number, no spaces.
Solve the equation.
Enter your answer as a number, no spaces.
Solve the equation.
Enter your answer as a number, no spaces.
Solve the equation. Check for extraneous solutions.
Use x={#, #} format, with exactly one space after the comma. List the smaller number first. If there is only one solution, use x={#} format. If there are no solutions, type "no solution" with no quote marks.
Solve the equation. Check for extraneous solutions.
Use x={#, #} format, with exactly one space after the comma. List the smaller number first. If there is only one solution, use x={#} format. If there are no solutions, type "no solution" with no quote marks.
Solve the equation. Check for extraneous solutions.
Use x={#, #} format, with exactly one space after the comma. List the smaller number first. If there is only one solution, use x={#} format. If there are no solutions, type "no solution" with no quote marks.
Dr. Demo solved the equation |x+2| = 2x+7 and got x={-5, -3}.
Is his solution correct? Why or why not?