1-6 Practice

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7 Nsɛmmisa

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Why is quadrilateral ABCD a rhombus?

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Which of the options below correctly explains why it is helpful to construct points D and A to be the same distance from C.

Because a line that is perpendicular to AB would be made of all points equidistant from points A and D.

Because point D is equidistant from points A and B.

Because circle A, circle D, and circle C all have the same radius.

Because segment CE needs to be congruent to segment AD in order for the lines to be perpendicular.

Because then you can construct at least three circles, which are necessary when constructing perpendicular lines.

Select all true statements.

A. Line EF is the bisector of angle BAC.

B. Line EF is the perpendicular bisector of segment BA.

C. Line EF is the perpendicular bisector of segment AC.

D. Line EF is the perpendicular bisector of segment BD.

E. Line EF is parallel to line CD.

Which line segment is congruent to HF?

A. AB

B. CD

C. DF

D. CB

Which of the options below correctly explains why segment EA is the same length as segment BC.

Because point A is the midpoint of segment EB.

Because figure ABCD is a square.

Because triangle ABC and triangle ABD are both equilateral and congruent.

Because line EB is the perpendicular bisector of segment CD.

Because the circles are congruent and EA & BC are both radii.

Is point M closer to point A, closer to point B, or the same distance from both points?

M is closer to point A.

M is the same distance from points A and B.

M is closer to point B.

There is not enough information to say whether M is closer to A or B.

Which of the options below correctly explains why the crease in the sheet of paper is the perpendicular bisector of segment AB?

Because the crease would be all points that are equidistant from A and B.

Because the crease would create a line that is parallel to segment AB.

Because the crease would pass through a circle with center at A, and passing though B.

Because the crease would touch neither point A or point B.

Becuase the crease would create a line that that passes through both points A and B.