The table in the 'show your work' section shows the results of a telephone survey asking adults if they intended to make online purchases in the next month.
Fill in the missing information:
Ask me to check your answers before you proceed.
The table in the 'show your work' section shows the results of a telephone survey asking adults if they intended to make online purchases in the next month.
Create a Venn Diagram to match the situation. Make sure to use all four numbers.
How many people in this data are males?
How many people in this data are males that intend to make an online purchase?
How many people are females that do not intend to make an online purchase?
Find the probability that a person chosen at random is a male.
Express your answer as a percent (one place past the decimal, use the % sign) or as a decimal proportion (three places past the decimal).
Find the probability that a person chosen at random is a female and intends to buy.
Express your answer as a percent (one place past the decimal, use the % sign) or as a decimal proportion (three places past the decimal).
Find the probability that a person chosen at random is a male and does not intend to buy.
Express your answer as a percent (one place past the decimal, use the % sign)
or
as a decimal proportion (three places past the decimal).
Find the probability that a person chosen at random intends to buy given that they are a female.
Express your answer as a percent (one place past the decimal, use the % sign)
or
as a decimal proportion (three places past the decimal).
Find the probability that a person chosen at random is a male given that they intend to buy online.
Express your answer as a percent (one place past the decimal, use the % sign)
or
as a decimal proportion (three places past the decimal).
Match the following statements with the correct probability notation.
| Draggable item | arrow_right_alt | Corresponding Item |
|---|---|---|
The probability the person is a female given they intend to buy. | arrow_right_alt | |
The probability the person does not intend to buy and is a female. | arrow_right_alt | |
The probability the person is a male or intends to buy online. | arrow_right_alt | |
The probability that a person intends to buy given that they are a male. | arrow_right_alt | |
The probability the person intends to buy and is not a female. | arrow_right_alt | |
The probability that a person is a male given they intend to buy. | arrow_right_alt |
A swim coach has 7 swimmers that he is teaching to be part of a 4-person relay team.
As the coach puts the swimmers into groups of 4 just to practice the relay, would this be a permutation or a combination?
Why?
A swim coach has 7 swimmers that he will enter to be part of a 4-person relay competition. He will use strategy to line them up, such as the fastest two swimmers are the lead and the anchor positions.
As the coach selects the swimmers to create his relay team, would this be a permutation or a combination?
Why?
New research (in 2023) has produced data that shows the distribution of M&M plain candy colors are: 20% red, 24% blue, 13% orange, 18% yellow and 7% brown. The remaining candies are green.
If you pick an M&M at random, what is the probability that it is green?
New research (in 2023) has produced data that shows the distribution of M&M plain candy colors are: 20% red, 24% blue, 13% orange, 18% yellow and 7% brown. The remaining candies are green.
If you pick an M&M at random, what is the probability that it is not green?
P(not green)= 1 - P(green)
New research (in 2023) has produced data that shows the distribution of M&M plain candy colors are: 20% red, 24% blue, 13% orange, 18% yellow and 7% brown. The remaining candies are green.
If you pick an M&M at random, what is the probability that it is pink or red?
P(pink or red)=
New research (in 2023) has produced data that shows the distribution of M&M plain candy colors are: 20% red, 24% blue, 13% orange, 18% yellow and 7% brown. The remaining candies are green.
If you pick three M&M’s (from a very very large bowl, 1000's, so they are independent).
What is the probability that they are all green?
P(green, green, green)=
Round to three or four places past the decimal.
New research (in 2023) has produced data that shows the distribution of M&M plain candy colors are: 20% red, 24% blue, 13% orange, 18% yellow and 7% brown. The remaining candies are green.
If you pick three M&M's, what is the probability that none are yellow?
Hints: P(not yellow) = 1 - P(yellow)
P(not yellow, not yellow, not yellow)=
Round to three or four places past the decimal.
New research (in 2023) has produced data that shows the distribution of M&M plain candy colors are: 20% red, 24% blue, 13% orange, 18% yellow and 7% brown. The remaining candies are green.
If you select three M&M's what is the probability at least one is yellow?
Remember:
'at least one' reminds us to use 1- the complement
P(at least one of the three is yellow) =1 - P(not yellow, not yellow, not yellow)=
New research (in 2023) has produced data that shows the distribution of M&M plain candy colors are: 20% red, 24% blue, 13% orange, 18% yellow and 7% brown. The remaining candies are green.
If you pick three M&M's what is the probability that the third M&M is the first one that is red?
Hint: P(not red, not red, red)=