A parallel plate capacitor has plates of area 0.880 m2, separated by a distance of 4.00 mm in a vacuum. It is connected to a dc source of potential difference 6.00 kV. Calculate: a the capacitance of the capacitor b the charge on one of the plates
c the electric field between the plates d the charge per unit area on one of the plates.
a the capacitance of the capacitor ( answer in nF)
b the charge on one of the plates
c the electric field between the plates
d the charge per unit area on one of the plates.
A parallel plate capacitor in a vacuum has a capacitance of 1.0 F. The plates are separated by a distance of 1 cm. Calculate the area of one of the capacitor plates. Comment on your answer.
Calculate the charge on one of the plates of a parallel plate capacitor of area 0.25m2.The plates are separated by a distance of 8.0 mm, in a vacuum.The potential difference across the plates is 24 V. ( answer in nC)
Two capacitors of capacitance 12pF and 4.0pF are connected in parallel to a source of potential difference 9.0 V. Calculate the charge on each capacitor. ( answer in pC)
Two capacitors of capacitance 12pF and 4.0pF are connected in series to a source of potential difference 6.0 V. Calculate the charge and potential difference on the 12 pF capacitor
Find the charge on and potential difference across each capacitor in the figure when points A and B are connected to a battery of emf 12V.The capacitors all have a capacitance of 12pF.

The figure shows two capacitors connected in a circuit.
The first capacitor has capacitance 3.20μF and has been charged by connecting it to a source of emf 12.0V.The other capacitor has capacitance 9.25μF and is initially uncharged.
When the switch is closed charge will move from one capacitor to the other. a Calculate the charge and potential difference for each capacitor after the switch is closed and charge no longer moves.

b Compare the energy stored before the switch is closed with that stored after the switch is closed.
c Comment on the answer to b.
A capacitor in a vacuum has capacitance 6.00pF and has been charged by a battery of emf 12.0V. a For the capacitor in vacuum, calculate the energy stored in the electric field. ( answer in pJ)
The battery is removed. A dielectric with ε = 6ε0 is now inserted in between the plates of the capacitor.
b Calculate the energy stored now.
c Compare the energies in a and b.