Stoich #2 Academic Chem w/ LR Practice

Last updated almost 3 years ago

7 questions

Stoich #2 Academic Chem w/ LR Practice

Last updated almost 3 years ago

7 questions

Question 1

What are the coefficients needed to balance the reaction: C4H10O + O2 --> CO2 + H2O

1, 3, 2, 5

1, 6, 4, 5

1, 6, 2, 3

1, 1, 1, 1

Question 2

Using the balanced chemical equation from question 1, determine how many moles of oxygen are needed to react with 3.45 moles of C4H10O. SHOW ALL WORK

3.45 moles of oxygen gas needed

662.4 g oxygen gas needed

8.95 g of oxygen gas needed

20.7 moles of oxygen gas needed

Question 3

Using the amount of moles you calculated that you need of oxygen from question 2, if you have 9.45 moles of oxygen gas available, what does that tell you about oxygen gas? SHOW ALL WORK.

the amounts of what you have and what you need are equal

oxygen gas is the limiting reagent because you have less then you need

there is no oxygen gas available so the reaction will not occur

oxygen gas is the excess reagent because you have more than you need

Question 4

What are the coefficients needed to balance the reaction: CsCl + O2 --> CsClO3

1, 1, 1

3, 2, 2

2, 3, 2

2, 3, 3

Question 5

Using the balanced chemical equation from question 4, when 4.5 mole of CsCl reacts with 5.80 moles of O2, determine which reactant is the limiting reagent.

O2 is the limiting reagent

There is no limiting reagent

CsCl is the limiting reagent

both reactants are limiting reagents

Question 6

When 10.5 g of potassium reacts with 12.1 g of cobalt (IV) fluoride, determine which is the limiting reagent using the balanced chemical equation below
4 K + CoF4 --> 4KF + Co

Cobalt (IV) fluoride is the limiting reagent because you have less than you need

Potassium is the excess reagent because you do not have enough cobalt (IV) fluoride

there is no limiting reagent, both are in excess

Potassium is the limiting reagent because you have more than enough cobalt (IV) fluoride

Question 7

Why do you calculate the limiting reagent? What is its use?

None of these

You calculate the limiting reagent to determine which reactant will run out first so that you can use the limiting reagent to calculate the theoretical yield of the products.

You calculate the limiting reagent to determine which reactant is the excess because the excess reagent runs out first.

You calculate the limiting reagent because the products are on the left side of the reaction.

Question 1

What are the coefficients needed to balance the reaction: C4H10O + O2 --> CO2 + H2O

1, 3, 2, 5

1, 6, 4, 5

1, 6, 2, 3

1, 1, 1, 1

Question 2

Using the balanced chemical equation from question 1, determine how many moles of oxygen are needed to react with 3.45 moles of C4H10O. SHOW ALL WORK

3.45 moles of oxygen gas needed

662.4 g oxygen gas needed

8.95 g of oxygen gas needed

20.7 moles of oxygen gas needed

Question 3

Using the amount of moles you calculated that you need of oxygen from question 2, if you have 9.45 moles of oxygen gas available, what does that tell you about oxygen gas? SHOW ALL WORK.

the amounts of what you have and what you need are equal

oxygen gas is the limiting reagent because you have less then you need

there is no oxygen gas available so the reaction will not occur

oxygen gas is the excess reagent because you have more than you need

Question 4

What are the coefficients needed to balance the reaction: CsCl + O2 --> CsClO3

1, 1, 1

3, 2, 2

2, 3, 2

2, 3, 3

Question 5

Using the balanced chemical equation from question 4, when 4.5 mole of CsCl reacts with 5.80 moles of O2, determine which reactant is the limiting reagent.

O2 is the limiting reagent

There is no limiting reagent

CsCl is the limiting reagent

both reactants are limiting reagents

Question 6

When 10.5 g of potassium reacts with 12.1 g of cobalt (IV) fluoride, determine which is the limiting reagent using the balanced chemical equation below
4 K + CoF4 --> 4KF + Co

Cobalt (IV) fluoride is the limiting reagent because you have less than you need

Potassium is the excess reagent because you do not have enough cobalt (IV) fluoride

there is no limiting reagent, both are in excess

Potassium is the limiting reagent because you have more than enough cobalt (IV) fluoride

Question 7

Why do you calculate the limiting reagent? What is its use?

None of these

You calculate the limiting reagent to determine which reactant will run out first so that you can use the limiting reagent to calculate the theoretical yield of the products.

You calculate the limiting reagent to determine which reactant is the excess because the excess reagent runs out first.

You calculate the limiting reagent because the products are on the left side of the reaction.

Stoich #2 Academic Chem w/ LR Practice

Stoich #2 Academic Chem w/ LR Practice

What are the coefficients needed to balance the reaction: C4H10O + O2 --> CO2 + H2O

Using the balanced chemical equation from question 1, determine how many moles of oxygen are needed to react with 3.45 moles of C4H10O. SHOW ALL WORK

Using the amount of moles you calculated that you need of oxygen from question 2, if you have 9.45 moles of oxygen gas available, what does that tell you about oxygen gas? SHOW ALL WORK.

What are the coefficients needed to balance the reaction: CsCl + O2 --> CsClO3

Using the balanced chemical equation from question 4, when 4.5 mole of CsCl reacts with 5.80 moles of O2, determine which reactant is the limiting reagent.

When 10.5 g of potassium reacts with 12.1 g of cobalt (IV) fluoride, determine which is the limiting reagent using the balanced chemical equation below4 K + CoF4 --> 4KF + Co

Why do you calculate the limiting reagent? What is its use?

What are the coefficients needed to balance the reaction: C4H10O + O2 --> CO2 + H2O

Using the balanced chemical equation from question 1, determine how many moles of oxygen are needed to react with 3.45 moles of C4H10O. SHOW ALL WORK

Using the amount of moles you calculated that you need of oxygen from question 2, if you have 9.45 moles of oxygen gas available, what does that tell you about oxygen gas? SHOW ALL WORK.

What are the coefficients needed to balance the reaction: CsCl + O2 --> CsClO3

Using the balanced chemical equation from question 4, when 4.5 mole of CsCl reacts with 5.80 moles of O2, determine which reactant is the limiting reagent.

When 10.5 g of potassium reacts with 12.1 g of cobalt (IV) fluoride, determine which is the limiting reagent using the balanced chemical equation below4 K + CoF4 --> 4KF + Co

Why do you calculate the limiting reagent? What is its use?

When 10.5 g of potassium reacts with 12.1 g of cobalt (IV) fluoride, determine which is the limiting reagent using the balanced chemical equation below
4 K + CoF4 --> 4KF + Co

When 10.5 g of potassium reacts with 12.1 g of cobalt (IV) fluoride, determine which is the limiting reagent using the balanced chemical equation below
4 K + CoF4 --> 4KF + Co