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Stoich #2 Academic Chem w/ LR Practice

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Last updated 24 days ago
7 questions
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2
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Question 1
1.

Question 2
2.

Question 3
3.

Question 4
4.

Question 5
5.

Question 6
6.

Question 7
7.

What are the coefficients needed to balance the reaction:          C4H10O   +   O2   -->  CO2   +  H2O
SHOW ALL WORK
1, 1, 1, 1
1, 3, 2, 5
1, 6, 2, 3
1, 6, 4, 5
Using the balanced chemical equation from question 1, determine how many moles of oxygen are needed to react with 3.45 moles of C4H10O. SHOW ALL WORK
3.45 moles of oxygen gas needed
662.4 g oxygen gas needed
8.95 g of oxygen gas needed
20.7 moles of oxygen gas needed
Using the amount of moles you calculated that you need of oxygen from question 2, if you have 9.45 moles of oxygen gas available, what does that tell you about oxygen gas?
oxygen gas is the limiting reagent because you have less then you need
oxygen gas is the excess reagent because you have more than you need
the amounts of what you have and what you need are equal
there is no oxygen gas available so the reaction will not occur
What are the coefficients needed to balance the reaction:               CsCl  +  O2   -->   CsClO3
SHOW ALL WORK
3, 2, 2
1, 1, 1
2, 3, 3
2, 3, 2
Using the balanced chemical equation from question 4, when 4.5 mole of CsCl reacts with 5.80 moles of O2, determine which reactant is the limiting reagent. SHOW ALL WORK
O2 is the limiting reagent
both reactants are limiting reagents
There is no limiting reagent
CsCl is the limiting reagent
When 10.5 g of potassium reacts with 12.1 g of cobalt (IV) fluoride, determine which is the limiting reagent using the balanced chemical equation below. SHOW ALL WORK
4 K  +   CoF4    -->   4KF   +  Co
Cobalt (IV) fluoride is the limiting reagent because you have less than you need
there is no limiting reagent, both are in excess
Potassium is the excess reagent because you do not have enough cobalt (IV) fluoride
Potassium is the limiting reagent because you have more than enough cobalt (IV) fluoride
Why do you calculate the limiting reagent?  What is its use?
You calculate the limiting reagent to determine which reactant is the excess because the excess reagent runs out first.
None of these
You calculate the limiting reagent because the products are on the left side of the reaction.
You calculate the limiting reagent to determine which reactant will run out first so that you can use the limiting reagent to calculate the theoretical yield of the products.