Lessons 7.1 & 7.2 Partner Content Check
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Last updated over 1 year ago
14 questions
Required
1
Tim purchased a random sample of clementines at a local grocery store. The 95% confidence interval for the mean weight of all clementines at this store is 76.6 grams to 90.1 grams. Interpret this confidence interval.
Tim purchased a random sample of clementines at a local grocery store. The 95% confidence interval for the mean weight of all clementines at this store is 76.6 grams to 90.1 grams. Interpret this confidence interval.
Required
2
Calculate the point estimate and margin of error used to create the confidence interval in #1.
Point estimate = _______
Margin of Error = _______
Required
2
The nutritional label on a bag of clementines says a typical clementine weighs 74 grams. Does the interval in #1 & 2 provide convincing evidence that the mean weight of clementines from this store is larger than the nutritional label suggests? Explain.
The nutritional label on a bag of clementines says a typical clementine weighs 74 grams. Does the interval in #1 & 2 provide convincing evidence that the mean weight of clementines from this store is larger than the nutritional label suggests?
Explain.
Required
1
The Pew Research Center and Smithsonian magazine recently quizzed a random sample of 1006 U.S. adults on their knowledge of science. One of the questions asked, “Which is the better way to determine whether a new drug is effective in treating a disease? If a scientist has a group of 1000 volunteers with the disease to study, should she (a) Give the drug to all of them and see how many get better or (b) Give the drug to half of them and not to the other half, and compare how many in each group get better?”
A 95% confidence interval for the proportion of U.S. adults who would correctly answer (b) is 0.723 to 0.777. Interpret this confidence interval. Use the sentence frame from our notes.I will grade your answer to this question by hand.
The Pew Research Center and Smithsonian magazine recently quizzed a random sample of 1006 U.S. adults on their knowledge of science.
One of the questions asked, “Which is the better way to determine whether a new drug is effective in treating a disease?
If a scientist has a group of 1000 volunteers with the disease to study, should she
(a) Give the drug to all of them and see how many get better or
(b) Give the drug to half of them and not to the other half, and compare how many in each group get better?”
A 95% confidence interval for the proportion of U.S. adults who would correctly answer (b) is 0.723 to 0.777.
Interpret this confidence interval. Use the sentence frame from our notes.
I will grade your answer to this question by hand.
Required
2
Calculate the point estimate and margin of error used to create the confidence interval in #4.
Point estimate = _______
Margin of Error = _______
Required
2
Refer to Exercise 4. If people guess one of the two choices at random, about 50% should get the answer correct. Does the interval in Exercise 4 provide convincing evidence that more than 50% of all U.S. adults would answer this question correctly? Explain.Hint: change 50% to a proportion to help answer.
Refer to Exercise 4.
If people guess one of the two choices at random, about 50% should get the answer correct. Does the interval in Exercise 4 provide convincing evidence that more than 50% of all U.S. adults would answer this question correctly?
Explain.
Hint: change 50% to a proportion to help answer.
Required
2
A magazine reported that 66% of all dog owners usually greet their dog before greeting their spouse or children when they return home at the end of the workday.
Researchers select 40 dog owners at random and ask them whom they greet first when returning home.
The 95% confidence interval for the proportion of owners who greet their dog first is 0.475 to 0.775.
Calculate the point estimate for the 95% confidence interval: _______
Calculate the margin of error for the 95% confidence interval: _______
Required
2
Refer to Exercise 7. Based on the confidence interval, is it plausible that the true proportion of all owners who greet their dog first is 66%? Explain.
Refer to Exercise 7.
Based on the confidence interval, is it plausible that the true proportion of all owners who greet their dog first is 66%? Explain.
Required
1
The puzzle editor of a game magazine asked 43 randomly selected subscribers how long it took them to complete a certain crossword puzzle. The 99% confidence interval for the median completion time for all subscribers is 15.2 to 18.6 minutes. Interpret the confidence level.CAUTION: The confidence level does not tell us the probability that a particular confidence interval captures the population parameter.
The puzzle editor of a game magazine asked 43 randomly selected subscribers how long it took them to complete a certain crossword puzzle.
The 99% confidence interval for the median completion time for all subscribers is 15.2 to 18.6 minutes.
Interpret the confidence level.
CAUTION: The confidence level does not tell us the probability that a particular confidence interval captures the population parameter.
Required
4
Explain what would happen in the following situations.
Explain what would happen in the following situations.
- Explain what would happen to the length of the interval if the sample size were increased to 100.
- Explain what would happen to the length of the interval if the sample size were decreased to 15.
- Explain what would happen to the length of the interval if the confidence level were increased to 100%
- Explain what would happen to the length of the interval if the confidence level were decreased to 90%
- Length of Confidence Interval would decrease
- Length of Confidence Interval would increase
Required
2
The puzzle editor originally sent requests for completion times to 150 subscribers, only 43 of whom reported their times. Describe one potential source of bias in the study that is not accounted for by the margin of error.
The puzzle editor originally sent requests for completion times to 150 subscribers, only 43 of whom reported their times.
Describe one potential source of bias in the study that is not accounted for by the margin of error.
Required
1
A Gallup poll asked a random sample of U.S. adults, “Would you like to lose weight?” Based on this poll, the 95% confidence interval for the proportion of all U.S. adults who want to lose weight is 0.56 to 0.62. Interpret the confidence level.I will grade this question by hand.
A Gallup poll asked a random sample of U.S. adults, “Would you like to lose weight?”
Based on this poll, the 95% confidence interval for the proportion of all U.S. adults who want to lose weight is 0.56 to 0.62.
Interpret the confidence level.
I will grade this question by hand.
Required
4
Match the scenario with what would happen to the confidence interval.
Match the scenario with what would happen to the confidence interval.
- Explain what would happen to the length of the interval if the confidence level were increased to 99%
- Explain what would happen to the length of the interval if the sample size was only half as big as in the actual study.
- Explain what would happen to the length of the interval if the sample size was twice as big as in the actual study.
- Explain what would happen to the length of the interval if the confidence level were decreased to 85%
- Confidence Interval would increase.
- Confidence interval would decrease.
Required
1
In the description of its methodology, Gallup states that the 3 percentage point margin of error for this poll includes only sampling variability (what it calls “sampling error”). What other potential sources of error (Gallup calls these “nonsampling errors”) could affect the accuracy of the 95% confidence interval?
Hint, what does the Margin of Error not account for?Explain how it could affect the results.I will grade this problem.
In the description of its methodology, Gallup states that the 3 percentage point margin of error for this poll includes only sampling variability (what it calls “sampling error”).
What other potential sources of error (Gallup calls these “nonsampling errors”) could affect the accuracy of the 95% confidence interval?
Hint, what does the Margin of Error not account for?
Explain how it could affect the results.
I will grade this problem.