Log in
Sign up for FREE
arrow_back
Library

Algebra Lesson 3-3 Quiz v2

star
star
star
star
star
Last updated over 2 years ago
6 questions
1
1.5
1
1
1
0
Question 1
1.

Inspect the graph below. What is the value of k?

Question 2
2.

Let f(x)=3x-1 and h(x)=f(-2x).

A. What is the slope-intercept equation for h(x), (something like h(x)=mx+b)?
B. What is the slope of h(x)?
C. What is the y-intercept of h(x)?

Question 3
3.

Question 4
4.

Question 5
5.

Question 6
6.

BONUS: Maximum 2 percentage points

Describe the domain and range of the function a(t) from the scenario above.

Select the equations that accurately match the graph.

f(x)=\frac{3}{2}x+2 \textrm{ and } g(x)=-\frac{3}{2}(-x)-2
f(x)=\frac{3}{2}x-2 \textrm{ and } g(x)=\frac{3}{2}x+2
f(x)=\frac{2}{3}x-2 \textrm{ and } g(x)=-\frac{2}{3}x+2
f(x)=-\frac{2}{3}x+2 \textrm{ and } g(x)=\frac{2}{3}x-2
If f(x)=\frac{7}{5}x-3 and g(x)=f(x+10), which equation defines g(x)?
g(x)=14x-3
g(x)=\frac{7}{5}x+11
g(x)=\frac{57}{5}x-3
g(x)=\frac{7}{5}x+7
Two marathon runners have each trained to run at perfectly consistent paces for the entire 26.2188 \textrm{ mi} of a marathon. Runner A's position along the marathon in miles is a function of how much time has passed in hours, given by a(t)=\frac{19}{4}t. For example, after \frac{12}{19} of an hour (60\frac{\textrm{min}}{\textrm{hr}}\times\frac{12}{19}\textrm{ hr}\approx 38 \textrm{ min}), runner A will have traveled a(\frac{12}{19})=\frac{19}{4}\cdot\frac{12}{19}=3\textrm{ mi}. If runner B finishes the marathon in just \frac{3}{4} the time it takes runner A, then what transformation of Runner A's graph describes the graph of runner B?
Runner B's graph is a horizontal stretch of \frac{4}{3}.
Runner B's graph is a vertical stretch of \frac{4}{3}.
Runner B's graph is a vertical translation of \frac{11}{8} units.
Runner B's graph is a horizontal translation of \frac{4}{3} units (left).