Solving Inequalities and Equations
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Last updated over 2 years ago
20 questions
Note from the author:
Many of the inequalities require that the students flip the sign of the inequality.
Solve the below inequalities and equations for x. Remember to flip the direction of the inequality symbol if both sides are multiplied or divided by a negative. So that your answers register as correct, put the X on the left side of the inequality symbol or equals sign.
1
1
-2x + 7 < 3x + 15
-2x + 7 < 3x + 15
1
-9x + 4 < -7x - 6
-9x + 4 < -7x - 6
1
2(x - 1) + 3 > 5x + 1
2(x - 1) + 3 > 5x + 1
1
-2x > -10
-2x > -10
1
-5x - 4 > 16
-5x - 4 > 16
1
-4x + 3 > -21
-4x + 3 > -21
1
4x - 4 < 15x + 7
4x - 4 < 15x + 7
1
-4(x+1) > 12
-4(x+1) > 12
1
-3(x+6) < 9 - 6x
-3(x+6) < 9 - 6x
1
2(x-1) = 3(x+2) - 5
2(x-1) = 3(x+2) - 5
1
2(X - 1) - 5 > X + 3
2(X - 1) - 5 > X + 3
1
\frac{3X+2}{5} = 2X+3
\frac{3X+2}{5} = 2X+3
1
\frac{2}{x} + 3 = 5
\frac{2}{x} + 3 = 5
1
\frac{X-2}{3} + \frac{4X+2}{2} = 2
\frac{X-2}{3} + \frac{4X+2}{2} = 2
1
\frac{X}{4} + 2 = \frac{3X}{8} - 1
\frac{X}{4} + 2 = \frac{3X}{8} - 1
1
\frac{X}{5} - \frac{1}{3} = \frac{4X - 1}{15}
\frac{X}{5} - \frac{1}{3} = \frac{4X - 1}{15}
1
\frac{9}{2x} = 3
\frac{9}{2x} = 3
1
\frac{3}{X} - \frac{4}{X} = \frac{9}{6}
\frac{3}{X} - \frac{4}{X} = \frac{9}{6}
1
\frac{X}{5} + 3 = \frac{X+10}{2} + \frac{X+6}{3}
\frac{X}{5} + 3 = \frac{X+10}{2} + \frac{X+6}{3}