Solving Inequalities and Equations

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Many of the inequalities require that the students flip the sign of the inequality.

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Solve the below inequalities and equations for x. Remember to flip the direction of the inequality symbol if both sides are multiplied or divided by a negative. So that your answers register as correct, put the X on the left side of the inequality symbol or equals sign.

-2x + 7 < 3x + 15

-9x + 4 < -7x - 6

2(x - 1) + 3 > 5x + 1

-2x > -10

-5x - 4 > 16

-4x + 3 > -21

Solving Inequalities and Equations

Solving Inequalities and Equations

-2x + 7 < 3x + 15

-9x + 4 < -7x - 6

2(x - 1) + 3 > 5x + 1

-2x > -10

-5x - 4 > 16

-4x + 3 > -21

4x - 4 < 15x + 7

-4(x+1) > 12

-3(x+6) < 9 - 6x

2(x-1) = 3(x+2) - 5

2(X - 1) - 5 > X + 3

\frac{3X+2}{5} = 2X+3

\frac{2}{x} + 3 = 5

\frac{X-2}{3} + \frac{4X+2}{2} = 2

\frac{X}{4} + 2 = \frac{3X}{8} - 1

\frac{X}{5} - \frac{1}{3} = \frac{4X - 1}{15}

\frac{9}{2x} = 3

\frac{3}{X} - \frac{4}{X} = \frac{9}{6}

\frac{X}{5} + 3 = \frac{X+10}{2} + \frac{X+6}{3}

-2x + 7 < 3x + 15

-9x + 4 < -7x - 6

2(x - 1) + 3 > 5x + 1

-2x > -10

-5x - 4 > 16

-4x + 3 > -21

4x - 4 < 15x + 7

-4(x+1) > 12

-3(x+6) < 9 - 6x

2(x-1) = 3(x+2) - 5

2(X - 1) - 5 > X + 3

\frac{3X+2}{5} = 2X+3

\frac{2}{x} + 3 = 5

\frac{X-2}{3} + \frac{4X+2}{2} = 2

\frac{X}{4} + 2 = \frac{3X}{8} - 1

\frac{X}{5} - \frac{1}{3} = \frac{4X - 1}{15}

\frac{9}{2x} = 3

\frac{3}{X} - \frac{4}{X} = \frac{9}{6}

\frac{X}{5} + 3 = \frac{X+10}{2} + \frac{X+6}{3}