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Laabri

3.05 Unit 3 Assessment

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Sickle Cell Anemia Case Study:

Hemoglobin is a crucial protein in red blood cells responsible for oxygen transport throughout the body. Sickle cell disease arises from a genetic mutation in the hemoglobin gene, leading to an amino acid substitution that causes the hemoglobin to clump together after releasing oxygen, distorting the red blood cells into a sickle shape. Individuals with two normal hemoglobin alleles (AA genotype) do not produce sickled cells. Those with one normal and one mutant allele (AS genotype) have sickle cell trait, producing both normal and sickled cells, primarily in low-oxygen conditions. Sickle cell disease occurs in individuals with two mutant alleles (SS genotype), leading to blockages in blood vessels due to the abnormal shape of red blood cells, resulting in severe pain, infections, and organ damage.

Genotype Key:

Normal = AA (Homozygous dominant)

Mostly Normal (Sickle Cell Trait) = AS (Heterozygous)

Sickle Cell Disease = SS (Homozygous recessive)

Asemmisa {{asɛmmisaAhyɛnsode}}
1.

Two individuals who carry the sickle cell trait, but do not have sickle cell anemia are pregnant with a child. What is the probability that the resulting child will inherit the sickle cell anemia disease?

Calculate the probability. Use the Punnett square provided to show your work.

% will inherit the sickle cell trait

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2.

Using the Punnett square that you created in question number 1, what is the probability that the resulting child would be a carrier (heterozygous) for the sickle cell anemia trait, but not have sickle cell anemia disease?

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3.

Using the Punnett square that you created in question number 1, what is the probability that the resulting child would have a normal phenotype (no sickle cell anemia)?

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4.

There are four main blood types: A, B, AB, and O. These types are based on the presence or absence of two antigens: antigen A and antigen B. Blood type A individuals have antigen A, blood type B individuals have antigen B, those with blood type AB have both antigens A and B, and individuals with blood type O have neither antigen.

The genotypes for blood type are determined by the combination of two alleles inherited from our parents. The three possible alleles are A, B, and O. A and B are co-dominant while O is recessive.

This chart describe the possible genotypes for each phenotype:

Is it possible for a child to have type O blood if their mother has type A blood and a father has type B blood?

Use the Punnett square to support your answer.

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Asemmisa {{asɛmmisaAhyɛnsode}}
5.

Use the FOIL method to determine the possible gametes for the F1 generation of Round Yellow peas.

What gametes are possible when the F1's cells go through meiosis?

First:

Inner:

HS-LS3-2

Autosomal Recessive Pedigree Directions:

Consider a pedigree that is tracking an autosomal dominant trait, where two recessive alleles (tt) result in the inability to taste a chemical known as PTC. The ability to taste PTC is determined by the presence of a dominant allele (T).

Complete the missing boxes in the chart below.

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Asemmisa {{asɛmmisaAhyɛnsode}}
12.

Draw a pedigree:

A couple with the ability to taste PTC have two grown sons and one grown daughter.

The sons have the ability to taste PTC. Their daughter is a PTC non-taster. She married a PTC non-taster man, and they have two sons.

Draw a pedigree in the box on the right that fully represents the above scenario and tracks the inability to taste PTC (non-taster), which is caused by two recessive “t” alleles.

In your illustrated pedigree, please make sure that:

(A) generations are listed as Roman numerals and the individuals are numbered.

(B) the correct shapes for males and females are used.

(C) the shapes that require shading are shaded.

(D) the genotypes are listed next to each pedigree shape.

*Hint: 1. Start by drawing the shapes and relationships in your pedigree, 2. then go back and list the genotype(s) next to each individual and finally, 3. shade where needed.

Asemmisa {{asɛmmisaAhyɛnsode}}
13.

Consider a population of mice with two phenotypes: black fur and white fur. The gene for fur color has two alleles: dominant black (F) and recessive white (f).

Which of the following is true about the genotype of the mouse shown below?

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14.

Two black-fur mice are bred, and have the litter shown below. What is the most likely explanation for the presence of the white-fur offspring?

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15.

Two mice with white fur are bred. What will be true of the offspring?

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16.

Consider a species of flower that follows incomplete dominance for color:

Complete a Punnett square for a cross between two pink flowers by clicking "Show Your Work."

Resulting genotypes:

Rr

red

white

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17.

A different species of flower follows codominance for color:

Complete a Punnett square for a cross between a red/white flower and a red flower by clicking "Show Your Work."

Resulting genotypes:

Rr

red

white

Asemmisa {{asɛmmisaAhyɛnsode}}
18.

What topics in this unit did you enjoy?

Which concepts did you find challenging?

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6.

Which choice would correctly complete this area on the chart? (Individual's Phenotype)

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7.

Which choice would correctly complete this area on the chart? (Shape in Pedigree)

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8.

Which choice would correctly complete this area on the chart? (Shaded?)

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9.

Which choice would correctly complete this area on the chart? (Individual's Phenotype)

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10.

Which choice would correctly complete this area on the chart? (Shape in Pedigree)

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11.

Which choice would correctly complete this area on the chart? (Shaded?)