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Homework: Logarithms

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Last updated about 1 year ago
12 questions
1
Question 10
10.
Convert this number into scientific notation:
A) .00000765 = _______ x 10 _______
Calculate the pH of this amount above using the formula
pH = - log10[H+]:
*if .00000765 is [H+]
B) pH = _______
Question 1 | 00:36
Question 2 | 00:58
Question 3 | 01:33
Question 4 | 01:50
Question 5 | 02:17
Question 6 | 02:24
Question 7 | 02:33
Question 8 | 02:45
Question 9 | 02:58
00:00/00:00
Question 1
00:36
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Question 2
00:58
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Question 3
01:33
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Question 4
01:50
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Question 5
02:17
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Question 6
02:24
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Question 7
02:33
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Question 8
02:45
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Question 9
02:58
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The measure of acidity of a liquid is called the pH of the liquid. This is based on the amount of hydrogen ions (H+) in the liquid. The formula for pH is:

pH = −log[H+]

where [H+] is the concentration of hydrogen ions, given in a unit called mol/L (“moles per liter”).

Liquids with a low pH (down to 0) are more acidic and those with a high pH are more basic.


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1
Question 12
12.
If the pH of a sample is 3.5. Then what is the [H+] concentration? Use the formula.
pH = −log[H+]

[H+] = _______
What is the above answer in scientific notation?
_______ x 10 _______
Question 1
1.
Logarithms help us deal with ___________________________________
Other Answer Choices:
factors
math
pi numbers
numbers that are multiplied
centered numbers
cheese and crackers
extremely big or small numbers
Question 2
2.

The logarithm of a number is the

Question 3
3.

What does the calculator button mean?

Question 4
4.
What is log264=_______
Question 5
5.
pH tells us how ____________________ a sample is.
Other Answer Choices:
additive or subtractive
kind
blue or red
acidic or basic
fishy and snapply
Question 6
6.

What is the formula for finding pH

Question 7
7.
Convert these two amounts to scientific notation:
A) .0000000398 = _______x 10 _______
B) .00000000398 = _______x 10 _______


Hint scientific notation:
.098 is 9.8 x 10-2
Question 8
8.
Calculate the pH of these two amounts using the formula.
A) .0000000398, pH = _______
B) .00000000398, pH = _______