Library

Semester Final CS3 (1/11/2024)

By Mickey Arnold
Last updated 10 months ago
16 Questions

What is output by the code below?
String[] ray;
ray = new String[4];
System.out.println( ray[0] );

What is output by the code below?
Integer[] ray;
ray = new Integer[4];
System.out.println( ray[3] );

What is output by the code below?
Integer[] ray;
ray = new Integer[4];
ray[1] = null;
ray[0] = new Integer(3);
ray[2] = new Integer(99);
System.out.println( ray[2] );

What is output by the code below?
Integer[] ray = {11,55,-4,909};
System.out.println( ray[3] );

What is output by the code below?
Double[] ray = {11.2,55.0,-4.5,909.0};
System.out.println( ray[1] );

What is output by the code below?
Double[] ray = {11.2,7.2,-4.5,909.0};
ray[1] = new Double(55.0);
System.out.println( ray[1] );

What is output by the code below?
Double[] ray = {3.2,5.7,6.3,1.9};
double x = 0;
for( double r : ray )
x += r;
System.out.println( x );

What is output by the code below?
Double[] ray = {3.1,5.2,6.3,1.4};
for( double r : ray )
r = 0;
System.out.println( ray[2] );

What is output by the code below?
String[] ray;
ray = new String[4];
ray[1] = "one";
System.out.println( ray[1] );

What is output by the code below?
String[] ray;
ray = new String[4];
ray[1] = "one";
ray[2] = "two";
ray[3] = "three";
System.out.println( ray[0] );

What do you call the condition that stops recursion?

What is returned the call fun(6) ?
public static int fun(int x)
{
if(x < 1)
return 1;
else
return x + fun(x - 1);
}

What is returned by the call fun(8) ?
public static int fun(int x)
{
if(x < 1)
return 1;
else
return x + fun(x - 1);
}

What is returned by the call fun(8) ?
public static int fun(int x){
if(x < 1)
return 1;
else
return x + fun(x - 2);
}

What is returned by the call fun(6) ?
public static int fun(int x){
if(x < 1)
return 1;
else
return x + fun(x - 2);
}

What is returned by the call fun(10) ?
public static int fun(int x)
{
if (x < 1)
return x;
else
return x + fun(x - 2);
}