DE Review of 1st semester

DeMorgan

Consensus

Distributive

Commutative

Multiplication

Associative

Boolean Algebra provides the ability to algebraically simplify logic expressions.

Boolean Algebra is the only way to simplify complex logic expressions.

Boolean Algebra uses many of the normal algebra rules such as commutative, associative and distribution laws.

Boolean Algebra creates simplified expressions that will result in a logic circuit that is equivalent to the original circuit, yet requires fewer gates.

4

11

102

51

47

11010

01111

01011

11110

10110

1

2

3

4

5

6

7

8

NAND

OR

AND

INVERTER

in parallel to a voltmeter

to measure total resistance

in parallel with the item being measured

in series with the item being measured

around a resistor

with a current limiting pull up reistor

56

27

72

53

35

65

1011 0101 1101

1110 1101 1101

1101 1011 0110

1011 1010 1101

1100 1011 1110

10111010

11100110

11100101

11010

01100111

6.4 Kilo Ohms, with a tolerance of 5%

6.4 Kilo Ohms, with a tolerance of 10%

6.4 Mega Ohms, with a tolerance of 10%

64 Mega Ohms, with a tolerance of 10%

6.4 Mega Ohms, with a tolerance of 5%

64 Mega Ohms, with a tolerance of 5%

Millifarads

Microvolts

Nanoamperes

Micro ohms

Microfarads

Milliamperes

231 Ohms, with a tolerance of 10%

23 Ohms, with a tolerance of 10%

23 Ohms, with a tolerance of 5%

230 Ohms, with a tolerance of 10%

231 Ohms, with a tolerance of 5%

2300 Ohms, with a tolerance of 10%

230 Ohms, with a tolerance of 5%

2300 Ohms, with a tolerance of 5%

instead of the battery

in series with the resistor

in series with the item being measured

between the ground and the battery

parallel to the item being measured

in series with the battery

resistance in parallel with a resistor

current in parallel with a resistor

pressure or force in parallel with a resistor

pressure or force in series with a resistor

current in series with a resistor

resistance in series with a resistor

the distance between the top of the wave and the bottom of the wave

one divided by the period

always above the zero line in analog waves

the percent of the time that the signal is low or high

the time between the beginning of a wave and the beginning of the next wave

the period divided by the amplitude

the frequency divided by the period

the height of the rising edge divided by the amplitude

the number of rising edges compared to the number of falling edges

the time high divided by the time low

how often the rising edge occurs

the time high divided by the period

00 = 0, 01 = 1, 10 = 1, 11 = 0

00 = 0, 01 = 0, 10 = 0, 11 = 1

00 = 1, 01 = 0, 10 = 0, 11 = 1

00 = 1, 01 = 1, 10 = 1, 11 = 0

00 = 0, 01 = 1, 10 = 1, 11 = 1

00 = 1, 01 = 0, 10 = 0, 11 = 0

boost a signal so that is is a higher amplitude.

to reverse the polarity of the circuit.

change the function of an AND gate to the function of an OR gate.

change a high signal to a low signal.

send electricity in the opposite direction.

change at +5V signal to a -5V signal.

only both input legs are high.

neither input leg is high.

both input legs are low.

both input legs are high and the output is low.

either or both of the inputs is high.

either input leg is high but the output is low.

A

B

C

D

Both B & C

In a parallel circuit, voltage is the same everywhere.

In a series circuit, amperage varies at each resistor.

In a series circuit, resistance is the same at all resistors.

In a series circuit, voltage is the same at all resistors.

In a parallel circuit, amperage is the same everywhere.

In a parallel circuit, resistance is the same everywhere.

Resistance equals voltage divided by current.

Voltage equals resistance divided by current.

Current equals resistance divided by voltage.

Current equals voltage times resistance.

Resistance equals voltage times current.

Voltage equals current divided by resistance.

add the resistances of all of the resistors.

take the resistance of the largest resistor.

multiply the amperage by the voltage.

take the reciprocal of the sum of the reciprocals.

multiply the number of resistors by the ohms of the largest resistor.

average the resistance of all the resistors.

add all the resistors together and divide into 1.

divide total resistance by the number of legs in the circuit.

take the average of all the resistances in the parallel legs.

divide each resistor into 1, add them together, then divide the answer into 1.

add the resistances of all of the resistors.

convert the circuit to series, then divide by the number of resistors.

XAND

SOR

XNOR

NOR

NAND

XOR

XOR

XAND

NAND

NOT

XAT

NOR

10^-12

10¹²

10⁶

10^-9

10⁹

10^-3

10³

10^-6

Amps

Volts

Watts

Joules

Farads

Ohms

Picos

18 mA

20 mA

50 mA

294 A

0 Ohm

50 Ohm

200 Ohm

500 Ohm

167 Ohm

1

2

3

4

5

6

7

8

1.2 x 10⁴

12,000 x 10³

12 x 10³

0.012 x 10-³

0.12 x 10⁵

330 pF

331 J

330 F

331 F

331 pF

1

2

3

4

5

6

7

2500 pf -20%, +50%

2500 f -20%, +50%

252 pf +/-10%

252 pf -20%, +50%

252 f -20%, +50%

2500 pf +/-10%

2500 f +/-10%

252 f +/-10%

6.5 x 10⁶ V

650 x 10⁶ V

66.5 x 10^-6 V

6.5 x 10^-6 V

650 x 10^-6 V

OR

NOR

INVERTER

AND

ground

VCC

resistor

output of the last logic gate

1000₂

0111₂

1100₂

1001₂

127₁₀

255₁₀

128₁₀

256₁₀

SOP logic

PSO logic

POS logic

SPO logic

001

011

101

All of the above

None of the above