Simplify this radical.
Use Completing the Square to solve this quadratic equation. Give all solutions in simplest form.
Use Completing the Square to solve this quadratic equation. Give all solutions in simplest form.
Use Completing the Square to solve this quadratic equation. Give all solutions in simplest form.
Use Completing the Square to solve this quadratic equation. Give all solutions in simplest form.
Match the graphs with their negative regions (below the x-axis).
| Draggable item | arrow_right_alt | Corresponding Item |
|---|---|---|
| arrow_right_alt | (-1, 3) |
| arrow_right_alt | (-∞, -1) and (3, ∞) |
| arrow_right_alt | (-3, 1) |
| arrow_right_alt | (-∞, -3) and (1, ∞) |
| arrow_right_alt | (-2, 4) |
| arrow_right_alt | (-∞, -2) and (4, ∞) |
| arrow_right_alt | (-4, 2) |
| arrow_right_alt | (-∞, -4) and (2, ∞) |
Use Your Vocabulary: Match each zero with its graph(s).
2
-2
1
-1
A swim team member performs a dive in the pool from a springboard.
The parabola below shows the path of her dive. Use the graph to answer the sorting question below.
Sort each statement into agree or disagree (based on the graph above)
The diver’s height was
decreasing the entire time.
The springboard was 14 feet high.
The diver reached her
maximum height at 23 feet in the air.
The diver landed in the water about 14 feet away from the springboard.
The diver’s range was between 0 and 23 feet.
The diver is going up in the air
between 0 < x < 3.
The diver was 4 feet away from the springboard when she reached her maximum height.
Between 3 feet from the springboard and 8 feet from the springboard, the diver’s height was decreasing.
When the diver was 5 feet away from the springboard, she was 19 feet high.
Using the graph, f(2) = 22.
The diver was again at the height of the springboard 6 feet away from the board.
The diver’s height was changing at a faster rate between 4 feet and 6 feet from the springboard versus 6 feet and 8 feet from the springboard.
Agree
Disagree
Match the statement to the quadratic equation it is describing.
My function's y-intercept and vertex are the same.
My function has a vertex that is (0, 0) and an axis of symmetry of x = 0.
My function is decreasing over the interval (-4, ∞).
My minimum is y=1 and
all the y-values of my function are positive.
I have an axis of symmetry of x = -1.
Find my function using the clue below:
f(-1) + f(4) = -11
The range of my function is y ≤ 1.
For my function, f(x) is negative when
x < 0 and x > 2.
The zeros of my parabola are (-6, 0) and (-2, 0).
My function is only increasing over the interval x > -1.
My y-intercept is 5
and my vertex is (-2, 1).
The x-intercepts of my parabola are opposites.
Match each equation to its graph
| Draggable item | arrow_right_alt | Corresponding Item |
|---|---|---|
| arrow_right_alt | f(x) = (x - 2)(x - 4) | |
| arrow_right_alt | f(x) = -(x + 2)(x - 2) | |
| arrow_right_alt | f(x) = (x + 2)(x - 4) |
Factor this quadratic function:
x2 - 3x - 4
Factor this quadratic function:
x2 + 3x - 10
Factor this quadratic function:
2x2 - 13x - 7
Factor this quadratic function:
4x2 - 15x - 25
