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1.8 Assignment (Module 4 Topic 1)

Last updated almost 2 years ago

6 Nsɛmmisa

1

Asemmisa {{asɛmmisaAhyɛnsode}}

1.

{\frac{x-1}{x+3}=\frac{x-2}{x+1}}

1

Asemmisa {{asɛmmisaAhyɛnsode}}

2.

{\frac{2x-1}{x+1}=\frac{2x-2}{x}}

1

Asemmisa {{asɛmmisaAhyɛnsode}}

3.

{\frac{x^2-1}{x-1}=\frac{x^2+1}{x+1}}

1

1

1

Asemmisa {{asɛmmisaAhyɛnsode}}

4.

{\frac{2}{x}-\frac{3}{2x}=\frac{1}{x^2}}

Asemmisa {{asɛmmisaAhyɛnsode}}

5.

{\frac{2}{x+3}+\frac{6}{x^2+3x}=\frac{1}{x}}

Asemmisa {{asɛmmisaAhyɛnsode}}

6.

{\frac{1}{x}+\frac{1}{x^2}=2}