1.8 Assignment (Module 4 Topic 1)
star
star
star
star
star
Last updated over 1 year ago
6 questions
1
{\frac{x-1}{x+3}=\frac{x-2}{x+1}}
{\frac{x-1}{x+3}=\frac{x-2}{x+1}}
1
{\frac{2x-1}{x+1}=\frac{2x-2}{x}}
{\frac{2x-1}{x+1}=\frac{2x-2}{x}}
1
{\frac{x^2-1}{x-1}=\frac{x^2+1}{x+1}}
{\frac{x^2-1}{x-1}=\frac{x^2+1}{x+1}}
1
{\frac{2}{x}-\frac{3}{2x}=\frac{1}{x^2}}
{\frac{2}{x}-\frac{3}{2x}=\frac{1}{x^2}}
1
{\frac{2}{x+3}+\frac{6}{x^2+3x}=\frac{1}{x}}
{\frac{2}{x+3}+\frac{6}{x^2+3x}=\frac{1}{x}}
1
{\frac{1}{x}+\frac{1}{x^2}=2}
{\frac{1}{x}+\frac{1}{x^2}=2}