Find the inverse of the function. Write your answer in {y=} form.
{y=3x^2}
{y=\sqrt{\frac{x}{10}}}
{y=x^{2}-4}
{y=\sqrt{x-8}}
{y=\frac{x+4}{5}}
{y=3x+7}
{y=\frac{x^{3}}{2}+9}
{y=\sqrt[3]{x+6}-1}