Twa kɔ nsɛm atitiriw so

Sign up for FREE

IM: 8.4.5: Solving Any Linear Equation (Practice)

Last updated over 1 year ago

9 Nsɛmmisa

Solve each of these equations. Explain or show your reasoning.

1

1

1

1

1

1

Asemmisa {{asɛmmisaAhyɛnsode}}

1.

2(x + 5) = 3x + 1

Asemmisa {{asɛmmisaAhyɛnsode}}

2.

3y - 4 = 6 - 2y

Asemmisa {{asɛmmisaAhyɛnsode}}

3.

3(n + 2) = 9(6 - n)

Asemmisa {{asɛmmisaAhyɛnsode}}

4.

Clare was solving an equation, but when she checked her answer she saw her solution was incorrect. She knows she made a mistake, but she can’t find it. Where is Clare’s mistake and what is the solution to the equation?
12(5 + 2y) = 4y - (5 - 9y)
72 + 24y = 4y - 5 - 9y
72 + 24y = -5y - 5
24y = -5y -77
29y = -77
y = -77/29

Solve each equation, and check your solution.

1

Asemmisa {{asɛmmisaAhyɛnsode}}

5.

1/9(2m - 16) = 1/3(2m +4)

1

Asemmisa {{asɛmmisaAhyɛnsode}}

6.

-4(r + 2) = 4(2 - 2r)

1

Asemmisa {{asɛmmisaAhyɛnsode}}

7.

12(5 + 2y) = 4y - (6 - 9y)

Asemmisa {{asɛmmisaAhyɛnsode}}

8.

Here is the graph of a linear equation.
Select all true statements about the line and its equation.

One solution of the equation is (3, 2).

One solution of the equation is (-1, 1).

One solution of the equation is (1, 3/2)

There are 2 solutions.

There are infinitely many solutions.

The equation of the line is y = 1/4x + 5/4.

The equation of the line is y = 5/4x + 1/4.

Asemmisa {{asɛmmisaAhyɛnsode}}

9.

A participant in a 21-mile walkathon walks at a steady rate of 3 miles per hour. He thinks, “The relationship between the number of miles left to walk and the number of hours I already walked can be represented by a line with slope -3.” Do you agree with his claim? Explain your reasoning.