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Laabri

Group I, Group VII and Group 0 Test revision

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Last updated 20 days ago
30 Nsɛmmisa
Hyɛ no nsow a efi ɔkyerɛwfo no hɔ:

This is a from to ensure that you do not miss any specification points 1.13-1.20

This is a from to ensure that you do not miss any specification points 1.13-1.20

Group I
1
1
6
6
9
Group VII
1
6
4
6
7
7
7
6
4
Balancing equations
1
3
4
5
4
3
4
5
3
4
Ɛhia
3
Ɛhia
4
Group 0 the noble gasses
1
3
4
4
Asemmisa {{asɛmmisaAhyɛnsode}}
1.

The periodic table

Asemmisa {{asɛmmisaAhyɛnsode}}
2.

The periodic table

Asemmisa {{asɛmmisaAhyɛnsode}}
3.

Sodium and potassium react with cold water to give similar products.

The electronic configuration of sodium is 2.8.1. The electronic configuration of potassium is 2.8.8.1. Explain the similarities and differences in the way sodium and potassium react with cold water by considering their reactions and their electronic configurations.

Then write out the answer as a model in your book

similarities

• both in the group (alkali metals)

• in a similar way

• Both have electron in their outer shell

• both produce and fizz (when reacted with

water)

• both produce alkaline solution (when

reacted with water)

2Na + 2H₂O → 2NaOH + H₂

2K + 2 H₂O → 2 KOH + H₂

differences

• potassium reactive

• potassium has a flame

• potassium outer electron from nucleus

• potassium has shells

• potassium has attraction of outer electron by nucleus

• potassium outer electron more easily

Mmuae Afoforo a Wobɛpaw:
weaker
lost
hydrogen
same
more
more
hydroxide
one
lilac
react
further
Asemmisa {{asɛmmisaAhyɛnsode}}
4.

The metals all , float and produce , the reactivity down the group because the outer is more easily .

potassium gives a flame

sodium gives a flame

2K + 2H₂O → 2 +

Now copy this into your books as a model answer.

and upload a photograph to this question.

Mmuae Afoforo a Wobɛpaw:
fizz
increases
yellow
electron
hydrogen
H₂
KOH
lilac
lost
Asemmisa {{asɛmmisaAhyɛnsode}}
5.

Match the statement to the alkali metal. Some statements apply to more than one metal. Focus simulation alkali metals.

K

Li

Na

Hardest to cut

floated on water

did not melt

Melted (formed a ball)

Easiest to cut

Formed a lilac flame

Reacted fastest

Reacted slowest

Asemmisa {{asɛmmisaAhyɛnsode}}
6.

Which letter shows iodine in cyclohexane?

Asemmisa {{asɛmmisaAhyɛnsode}}
7.

I₂

Cl₂

Br₂

Dark grey

Gas at room temperature

Liquid at room temperature

Pale green

Red - brown

Solid at room temperature

Asemmisa {{asɛmmisaAhyɛnsode}}
8.

Halogens

Pale green

Red - brown

Dark grey

Gas

Purple

What colour is chlorine?

What colour is bromine?

What colour is solid iodine ?

What colour are iodine vapours

Asemmisa {{asɛmmisaAhyɛnsode}}
9.

Halogens

Starch

Colourless

Liquid

Solid

What can be used to test for iodine?

What colour (if any) is sodium chloride

What is the state of bromine at room temperature?

What is the state of iodine at room temperature?

What colour (if any) is sodium bromide

What colour (if any) is sodium iodide

Asemmisa {{asɛmmisaAhyɛnsode}}
10.

Chlorine + sodium chloride → so solution stays

Chlorine + sodium bromide →+ so solution turns

Chlorine + sodium iodide →+ so solution turns (would be in organic solvent)

Mmuae Afoforo a Wobɛpaw:
pale green
sodium iodide
orange
bromine
brown
sodium chloride
colourless
purple
No reaction
iodine
Asemmisa {{asɛmmisaAhyɛnsode}}
11.

Bromine + sodium chloride → so solution stays

Bromine + sodium bromide →+ so solution stays

Bromine + sodium iodide →+ so solution turns (would be in organic solvent)

Mmuae Afoforo a Wobɛpaw:
colourless
No reaction
brown
iodine
sodium bromide
orange
bromine
purple
Asemmisa {{asɛmmisaAhyɛnsode}}
12.

Iodine + sodium chloride → so solution stays (would be

in organic solvent)

Iodine + sodium bromide →so solution stays

(would be in organic solvent)

Iodine + sodium iodide →so solution stays (would be in organic solvent)

Mmuae Afoforo a Wobɛpaw:
purple
brown
No reaction
colourless
Asemmisa {{asɛmmisaAhyɛnsode}}
13.

6 mark halogen displacement question

Write this into your book as a model answer.

Order of reactivity: > >

Experiment 1

add (aqueous) chlorine to a solution of potassium bromide the solution turns as bromine is produced.

Conclusion:

chlorine bromine

Full equation

Cl₂ + 2KBr → Br₂ + 2KCl

Experiment 2

add aqueous bromine to a solution of potassium iodide the solution turns as iodine is produced

Conclusion:

bromine is reactive than iodine

Br₂ + 2KI → I₂ + 2KBr

Experiment 3

add aqueous chlorine to a solution of potassium iodide the solution turns as iodine is produced

Conclusion

(so) chlorine is more reactive than iodine

Cl₂ + 2KI → I₂ + 2KCl

Mmuae Afoforo a Wobɛpaw:
bromine
chlorine
brown
more
displaces
orange
ionic
iodine
Asemmisa {{asɛmmisaAhyɛnsode}}
14.

Chlorine gas is

Bromine liquid is

Iodine solid is dark

Iodine gas is

Mmuae Afoforo a Wobɛpaw:
pale green
dark grey
purple
red -brown
Asemmisa {{asɛmmisaAhyɛnsode}}
15.

C + O₂ ⟶ CO₂

Asemmisa {{asɛmmisaAhyɛnsode}}
16.

H₂ + O₂ ⟶ H₂O

Asemmisa {{asɛmmisaAhyɛnsode}}
17.

NaOH + HCl ⟶ NaCl + H₂O

NaOH + HCl ⟶ NaCl + H₂O

Asemmisa {{asɛmmisaAhyɛnsode}}
18.

Na₂CO₃ + HCl ⟶ NaCl + H₂O + CO₂

Asemmisa {{asɛmmisaAhyɛnsode}}
19.

Na + H₂O ⟶ NaOH + H₂

Asemmisa {{asɛmmisaAhyɛnsode}}
20.

Na + Cl₂ ⟶ NaCl

Asemmisa {{asɛmmisaAhyɛnsode}}
21.

NaOH + H₂SO₄ ⟶ Na₂SO₄ + H₂O

Asemmisa {{asɛmmisaAhyɛnsode}}
22.

Na₂CO₃ + HCl ⟶ NaCl + H₂O + CO₂

Asemmisa {{asɛmmisaAhyɛnsode}}
23.

N2 + H2 ⟶ NH3

Asemmisa {{asɛmmisaAhyɛnsode}}
24.

Complete combustion of methane

CH4 + O2 ⟶ CO2 + H2O

Asemmisa {{asɛmmisaAhyɛnsode}}
25.

Balance this equation: O2 → Mg + Mg(OH)2 +

Asemmisa {{asɛmmisaAhyɛnsode}}
28.

Neon is used in light bulbs because it is and so does not react with the filament whereas would react with the tungsten filament.

Neon is inert because it has a outer shell of electrons so does not need to , gain or lose electrons to get a full outer shell

Mmuae Afoforo a Wobɛpaw:
full
tungsten
inert
oxygen
share
Asemmisa {{asɛmmisaAhyɛnsode}}
29.

Argon is used in welding as it is and it stops the metal reacting with the in the air so a strong join is achieved.

Argon is inert because it has a outer shell of electrons so does not need to ,

share or lose electrons to get a full outer shell.

Mmuae Afoforo a Wobɛpaw:
full
inert
gain
oxygen
Asemmisa {{asɛmmisaAhyɛnsode}}
30.

Helium is used in weather balloons because it is dense than air.

Helium is used instead of hydrogen because helium is so will not react with oxygen, whereas hydrogen is very and would react explosivley with the oxygen in the air.

Helium is inert because it has a full outer shell of electrons so it does not need to share, gain or electrons to get a full outer shell.

Mmuae Afoforo a Wobɛpaw:
less
inert
lose
reactive

Use the diagrams to answer the questions