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Energetics 2 Worked examples Ea from graph

Last updated over 1 year ago

11 Nsɛmmisa

Ea from graph

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Born Haber Cycles and calculations

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1

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Asemmisa {{asɛmmisaAhyɛnsode}}

1.

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Gradient = K

Ea = kJmol^-1

Asemmisa {{asɛmmisaAhyɛnsode}}

2.

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(i) = x 10^-3

(ii) =

E_A =

Asemmisa {{asɛmmisaAhyɛnsode}}

3.

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Value 1 = x10^-3

Value 2 =

Gradient =

E_A = kJ mol^-1

Asemmisa {{asɛmmisaAhyɛnsode}}

4.

ionic solid

Mmuae Afoforo a Wobɛpaw:

Elements in standard states

gaseous ions

Ionic lattice

Asemmisa {{asɛmmisaAhyɛnsode}}

5.

Mmuae Afoforo a Wobɛpaw:

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(dissociation)

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Asemmisa {{asɛmmisaAhyɛnsode}}

6.

Mmuae Afoforo a Wobɛpaw:

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Asemmisa {{asɛmmisaAhyɛnsode}}

7.

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Born Haber cycle = 𝟏/𝟐 E(F–F) + 732 + 289 + +203 = 348 + 955

1/2 bond Enthalpy (F-F) = kJmol^-1

Bond enthalpy = kJmol^-1

Asemmisa {{asɛmmisaAhyɛnsode}}

8.

null

Experimental lattice enthalpy value allows for:

includes interaction ( non–spherical ions / distorted ions / polarisation)

OR AgF has character

Theoretical lattice enthalpy value assumes only interaction

(point charges / no character / perfect spheres )

OR AgF is not perfectly )

Mmuae Afoforo a Wobɛpaw:

ionic

covalent

Asemmisa {{asɛmmisaAhyɛnsode}}

9.

Comparing lattice enthalpies

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Chloride ion than fluoride ion

Attraction between Ag⁺ and Cl ^– .

Mmuae Afoforo a Wobɛpaw:

larger

weaker

Asemmisa {{asɛmmisaAhyɛnsode}}

10.

Enthalpy of hydration calculation

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Enthalpy change when of a ion forms ions

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+77 = +905 – 464 + ∆H(hydration, Cl^– )

Mmuae Afoforo a Wobɛpaw:

gaseous

–364 (kJ mol^–1 )

1 mol

aqueous

Asemmisa {{asɛmmisaAhyɛnsode}}

11.

null

Mastered