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Biblioteka

Energetics 2 Worked examples Ea from graph

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11
Ea from graph
1
1
1
Born Haber Cycles and calculations
3
1
1
3
1
1
1
1
Pitanje 1
1.

Gradient = K

Ea = kJmol-1

Pitanje 2
2.

(i) = x 10-3

(ii) =

EA =

Pitanje 3
3.

Value 1 = x10-3

Value 2 =

Gradient =

EA = kJ mol-1

Pitanje 4
4.

ionic solid

Drugi mogući odgovor:
Elements in standard states
gaseous ions
Ionic lattice
Pitanje 5
5.
Drugi mogući odgovor:

(dissociation)

Pitanje 6
6.
Drugi mogući odgovor:

Pitanje 7
7.

Born Haber cycle = 𝟏/𝟐 E(F–F) + 732 + 289 + +203 = 348 + 955

1/2 bond Enthalpy (F-F) = kJmol-1

Bond enthalpy = kJmol-1

Pitanje 8
8.

Experimental lattice enthalpy value allows for:

includes interaction ( non–spherical ions / distorted ions / polarisation)

OR AgF has character

Theoretical lattice enthalpy value assumes only interaction

(point charges / no character / perfect spheres )

OR AgF is not perfectly )

Drugi mogući odgovor:
ionic
covalent
Pitanje 9
9.

Comparing lattice enthalpies

Chloride ion than fluoride ion

Attraction between Ag+ and Cl – .

Drugi mogući odgovor:
larger
weaker
Pitanje 10
10.

Enthalpy of hydration calculation

Enthalpy change when of a ion forms ions

+77 = +905 – 464 + ∆H(hydration, Cl– )

Drugi mogući odgovor:
gaseous

–364 (kJ mol–1 )

1 mol
aqueous
Pitanje 11
11.

Mastered