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2Pb(OH)2 + HF → 2H2O + PbF2
There are
2Pb(OH)2 + HF → 2H2O + PbF2
How many pre-existing molecules of OH are there?
2Pb(OH)2 + HF → 2H2O + PbF2
The total number of atoms on the product side is
2Pb(OH)2 + HF → 2H2O + PbF2
This chemical equation is
2Pb(OH)2 + HF → 2H2O + PbF2
Select every element that you put a ≠ between. (which ones had different counts)