
2Al(CO3)3 → 2Al2O3 + 6CO2
There are
2Al(CO3)3 → 2Al2O3 + 6CO2
How many pre-existing molecules of CO3 are there?
2Al(CO3)3 → 2Al2O3 + 6CO2
The total number of atoms on the reactant side is
2Al(CO3)3 → 2Al2O3 + 6CO2
This chemical equation is
2Al(CO3)3 + → 2Al2O3 + 6CO2
Select every element that you put a ≠ between. (which ones had different counts)