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Year 11 post test MTD calculation practice

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Last updated over 1 year ago
9 Nsɛmmisa
Hyɛ no nsow a efi ɔkyerɛwfo no hɔ:

Calculation practice post RGSHW end of topic test on calculations

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Asemmisa {{asɛmmisaAhyɛnsode}}
1.

GCSE target grade

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2.

GCSE grade in last test

Asemmisa {{asɛmmisaAhyɛnsode}}
3.

Moles required = C x V = moles.

RFM of sodium carbonate =

mass = moles x RFM. = g.

Asemmisa {{asɛmmisaAhyɛnsode}}
4.

(b) (i) CO32- + 2H+ -> CO2 + H2O

(b) (ii) moles sodium carbonate = C x V =

moles HCl = 2 x moles of sodium carbonate =

concentration of HCl = moles / volume = mol/dm3

Asemmisa {{asɛmmisaAhyɛnsode}}
5.

RFM glucose =

moles = mass / RFM =

moles ethanol = 2 x mol glucose =

RFM ethanol =

mass of ethanol = moles x RFM = g

Moles carbon dioxide = moles of ethanol =

Volume of carbon dioxide = moles x volume (of one mole) = cm3

Volume of carbon dioxide in dm3 - =

Calculate the atom economy if ethanol is the only desired product.

Atom economy = mass of desired product / total mass of products x 100 %

Asemmisa {{asɛmmisaAhyɛnsode}}
6.

Moles Ag = mass / RAM =

Moles Cu = Moles Ag / 2 =

Mass Cu = Moles Cu x RAM = g

Asemmisa {{asɛmmisaAhyɛnsode}}
7.

Moles of oxygen = mass / RAM =

Moles of tin = mass /RAM =

Divide both values by the smallest value to get SnO

Asemmisa {{asɛmmisaAhyɛnsode}}
8.

Volume in dm3 = volume in cm3 / 1000 =

Concentration = mass / volume = g/dm3

Or just use logic if I have a 1/4 of the volume I will have a 1/4 of the mass so the full mass is 4 x mass in 250cm3

Asemmisa {{asɛmmisaAhyɛnsode}}
9.

I feel more confident in this topic having completed the Formative