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Geometry - Unit 4 - Lesson 6 & 7

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Last updated about 1 year ago
9 questions
Required
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
Question 1
1.

Select all true statements:

Question 2
2.
Find m\angle{A} and m\angle{B} in the picture below. Round your answer to the nearest whole degree.

m\angle{A}=_______
m\angle{B}=_______
Question 3
3.
Write an expression that can be used to find the length of JH. Use angle G to find your solution.

JH=______________________________

JH=__________
Question 4
4.
Write an expression that can be used to find the length of GJ. Use angle G to find your solution.

GJ=______________________________

GJ=__________
Question 5
5.

Find the length of the hypotenuse in the above triangle.
x=_______
Question 6
6.
Find the measure of each of the acute angles in the triangle below. Round your answers to the nearest whole degree.

The length of the angle to the right of the side that is 5 mi is _______ degrees, and the angle at the top of the triangle is _______ degrees.
Question 7
7.

Draggable itemarrow_right_altCorresponding Item
arrow_right_alt
arrow_right_alt
arrow_right_alt
arrow_right_alt
arrow_right_alt
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Question 8
8.

Find the length of QP.

Question 9
9.

Find the length of RQ. Leave your answer in simplest radical form. (Hint: Use your 30-60-90 triangle rules.)

cos(B)=\frac{4}{\sqrt{97}}
tan(B)=\frac{9}{4}
4^{2}+9^{2}=97
tan(B)=\frac{4}{9}
Approximate the angle (to the nearest degree) that has the following quotient:
\frac{adjacent leg}{hypotenuse}=0.682
15\degree
\frac{opposite leg}{hypotenuse}=0.469
28\degree
\frac{opposite leg}{hypotenuse}=0.848
72\degree
\frac{adjacent leg}{hypotenuse}=0.966
46\degree
\frac{adjacent leg}{hypotenuse}=0.139
14\degree
\frac{opposite leg}{adjacent leg}=0.249
47\degree
\frac{opposite leg}{adjacent leg}=1.036
58\degree
\frac{adjacent leg}{hypotenuse}=0.309
82\degree