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Laabri

Geometry - Unit 4 - Lesson 6 & 7

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Last updated over 1 year ago
9 Nsɛmmisa
Ɛhia
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
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G.SRT.6
N.Q.3
Asemmisa {{asɛmmisaAhyɛnsode}}
1.

Select all true statements:

Asemmisa {{asɛmmisaAhyɛnsode}}
2.

Find m\angle{A} and m\angle{B} in the picture below. Round your answer to the nearest whole degree.

m\angle{A}=

m\angle{B}=

Asemmisa {{asɛmmisaAhyɛnsode}}
3.

Write an expression that can be used to find the length of JH. Use angle G to find your solution.

JH=

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4.

Write an expression that can be used to find the length of GJ. Use angle G to find your solution.

GJ=

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5.

Find the length of the hypotenuse in the above triangle.

x=

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6.

Find the measure of each of the acute angles in the triangle below. Round your answers to the nearest whole degree.

The length of the angle to the right of the side that is 5 mi is degrees, and the angle at the top of the triangle is degrees.

Asemmisa {{asɛmmisaAhyɛnsode}}
7.

Approximate the angle (to the nearest degree) that has the following quotient:

Draggable itemarrow_right_altCorresponding Item

\frac{opposite leg}{hypotenuse}=0.469

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15\degree

\frac{adjacent leg}{hypotenuse}=0.139

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28\degree

\frac{opposite leg}{adjacent leg}=0.249

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72\degree

\frac{adjacent leg}{hypotenuse}=0.682

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46\degree

\frac{opposite leg}{hypotenuse}=0.848

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14\degree

\frac{adjacent leg}{hypotenuse}=0.309

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47\degree

\frac{adjacent leg}{hypotenuse}=0.966

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58\degree

\frac{opposite leg}{adjacent leg}=1.036

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82\degree

Asemmisa {{asɛmmisaAhyɛnsode}}
8.

Find the length of QP.

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9.

Find the length of RQ. Leave your answer in simplest radical form. (Hint: Use your 30-60-90 triangle rules.)