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Laabri

Precalculus Chapter 3 Quiz

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Last updated 20 days ago
13 Nsɛmmisa

Directions: For 1-5, determine whether each of the following statements is sometimes, always, or never true.

0.5
0.5
N 404
0.5
F501
0.5
A503
1
1
A405
1
A504

On the axes provided, graph the set of all $(x, y)$ satisfying the given inequality:

1
AF503
1
A506
1
A508
1
A604
1
A604
0
Asemmisa {{asɛmmisaAhyɛnsode}}
1.

If $a < b$ and $0 > c$, then $ac = bc$.

Asemmisa {{asɛmmisaAhyɛnsode}}
2.

If $|x - 2| < 3$, then the distance from $x$ to 2 is less than 3.

Asemmisa {{asɛmmisaAhyɛnsode}}
3.

A polynomial changes sign at each of its zeros.

Asemmisa {{asɛmmisaAhyɛnsode}}
4.

If a line has equation $y = mx + k$, any point $(x, y)$ below the line satisfies the inequality $y > mx + k$.

Asemmisa {{asɛmmisaAhyɛnsode}}
5.

If a linear expression $P = Ax + By$ is evaluated for all points of a convex polygonal feasible region, the maximum and minimum values (if they exist) will occur at a corner point.

Asemmisa {{asɛmmisaAhyɛnsode}}
6.

Solve and graph the inequality.

$\frac{5 - 4x}{2} < -3x$

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
Asemmisa {{asɛmmisaAhyɛnsode}}
7.

Solve and graph the inequality.

$|x - 4| < 3$

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
Asemmisa {{asɛmmisaAhyɛnsode}}
8.

$3x - 2y > 4$

Asemmisa {{asɛmmisaAhyɛnsode}}
9.

$y > x^2 - 9$

Asemmisa {{asɛmmisaAhyɛnsode}}
10.

$y < x^3 - x^2 - 9x + 9$

Asemmisa {{asɛmmisaAhyɛnsode}}
11.

Graph the solution set of the system of inequalities:

$x \ge 0$

$2x+y \ge 4$

Asemmisa {{asɛmmisaAhyɛnsode}}
12.

Graph the solution set of the system of inequalities:

$y < x$

$y \ge x^2 -1$

Asemmisa {{asɛmmisaAhyɛnsode}}
13.

Challenge

Solve: $\frac{|x|}{x - 2} < 2$