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Laabri

S1W5 2d motion practice

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Last updated 10 months ago
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Asemmisa {{asɛmmisaAhyɛnsode}}
1.

When dealing with two dimensional motion, you can decompose all vectors into horizontal and vertical and deal with each one separately.

Asemmisa {{asɛmmisaAhyɛnsode}}
2.

Let's review the equations we have seen so far.

this equation tells you that velocity v is

Asemmisa {{asɛmmisaAhyɛnsode}}
3.

in 1D, a question using this equation might look like this - Hannah starts her sprint at 10m left of the door and ends her spring after 5 seconds 15m right of the door. Use the equation above to find Hannah's velocity. We are going to call the direction to the right positive.

Asemmisa {{asɛmmisaAhyɛnsode}}
4.

I'm stepping you through that one just to make sure - The initial position is -10 (because it is to the left of the door, it is negative). and the final position is 15, which is positive because it is to the right of the door. If I want to find the distance between them, I would subtract . $x_f -x_i = 15--10 = 15+10$Show the two points and the line between them on the number line below.

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
Asemmisa {{asɛmmisaAhyɛnsode}}
5.

what does finding the displacemeent look like in 2D? Saw you start at $15\hat i+10\hat j$ and end at $20\hat i +3\hat j$,

put the initial point and final point on the graph below (it doesn't let you add a line or an arrow, convince yourself which direction it should go. )

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi ka ho. Twe asɛm bi anaa kyerɛw x ne y coordinates na sesa ne gyinabea. Klik asɛm bi so na popa.
Asemmisa {{asɛmmisaAhyɛnsode}}
6.

in 2d, you do the EXACT same thing as 1D. you subtract the final point from the initial point. If you start at $15\hat i+10\hat j$ and end at $20\hat i +3\hat j$, you subtract the first position from the final position
$(20\hat i+3\hat j )-(15\hat i+10\hat j)$What you are going to do is separate the $\hat i$ and the $\hat j$ parts and subtract them separately.

$20\hat i-15\hat i$ and $3\hat j-10\hat j$

do you have any questions about this?

Asemmisa {{asɛmmisaAhyɛnsode}}
7.

If you have a plane that has a velocity of $15\hat i +6\hat j$ with regards to the ground, and there is a wind blowing at $-12\hat i +7\hat j$. What would the plane's velocity be if there was no wind?
$\hat i$ +$\hat j$

Asemmisa {{asɛmmisaAhyɛnsode}}
8.

The final velocity for the above problem is \hat i+ \hat j

Asemmisa {{asɛmmisaAhyɛnsode}}
9.

If you have a plane that in a windless day has a velocity of $6\hat i + 3\hat j$$\frac{m}{s}$. If a wind started blowing at $5\hat i +9\hat j$ $\frac{m}{s}$ how fast would the total velocity of the plane be?

$\hat i +$ $\hat j$

Asemmisa {{asɛmmisaAhyɛnsode}}
10.

Watch the following video

do you have any questions?

Asemmisa {{asɛmmisaAhyɛnsode}}
11.

think about the kid who throws a ball straight up in the air in a car. Explain why his answer, the ball would land right back down on the person, would only work in ideal physics land.

Asemmisa {{asɛmmisaAhyɛnsode}}
12.

if you throw a ball straight up in the air when you are driving in a non-convertible car, does the ball whack you in the face because of projectile motion?

Asemmisa {{asɛmmisaAhyɛnsode}}
13.
Mmuae Afoforo a Wobɛpaw:

when the velocity in the y direction is 0

initial x and y direction, and where the initial velocities in the x and y directions would be measured.

a point where my y velocity is negative

when the y position is 0

a point where my y velocity is positive

Asemmisa {{asɛmmisaAhyɛnsode}}
14.

Consider the following question - a cannon is shot with an initial velocity of 3\hat i+5\hat j m/s it's initial position in meters is at (0,1). The cannonball takes 4 seconds to hit the ground. how far did the cannon move horizontally when it hits the ground? Assume no air resistance

Using the GUESS method:

Givens - = 3 m/s, =5 m/s, = 0m, =1 m, =4 s, = -10 m/s^2 (assumed, not given), =0 m/s^2

Unknowns

Mmuae Afoforo a Wobɛpaw:
position in the x direction when the ball hits the ground
Initial velocity in the x direction
initial position on the x axis
acceleration in the x direction
time
initial velocity in the y direction
Acceleration due to gravity
initial position in the y direction.
Asemmisa {{asɛmmisaAhyɛnsode}}
15.

Which equation do i want? (you may want to look at the equation material on google classroom.

Equations I want in verbal form

equation I want in symbol form

Mmuae Afoforo a Wobɛpaw:

position in the x direction

position in the y direction
Velocity in the y direction

velocity in the x direction

Asemmisa {{asɛmmisaAhyɛnsode}}
16.

SUBSTITUTE: Which of the following represents the correct values being substituted into the correct equation?

Asemmisa {{asɛmmisaAhyɛnsode}}
17.

SOLVE: how far did the cannonball move horizontally?

Asemmisa {{asɛmmisaAhyɛnsode}}
18.

Consider the following question - a cannon is shot with an initial velocity of 2\hat i+6\hat j m/s? it's initial position in meters is at (0,1). When does the cannonball reach its highest point Assume no air resistance

Using the GUESS method:

Givens - = 2 m/s, =6 m/s, = 0, =1 m, = -10 m/s m/s^2 (assumed, not given), =0

Unknowns

Mmuae Afoforo a Wobɛpaw:
initial position on the x axis
acceleration in the x direction
Initial velocity in the x direction
time
initial position in the y direction.
Acceleration due to gravity
initial velocity in the y direction
Asemmisa {{asɛmmisaAhyɛnsode}}
19.

Which equation do i want? (you may want to look at the equation material on google classroom.

Equations I want in verbal form

equation I want in symbol form

Mmuae Afoforo a Wobɛpaw:
position in the x direction

Velocity in the y direction
position in the y direction

velocity in the x direction
Asemmisa {{asɛmmisaAhyɛnsode}}
20.

Substitute: which equation works for what you are trying to find?

Asemmisa {{asɛmmisaAhyɛnsode}}
21.

consider the following problem: the hangtime of a basketball player who jumps a vertical distance of 2 feet (0.6 m) is about 2/3 s. what will be the hangtime of a player that can jump 1.4 feet (1.2 m) horizontally?
what equation would be best for working this out?

Asemmisa {{asɛmmisaAhyɛnsode}}
22.

What is your intuition of what the answer is?

Asemmisa {{asɛmmisaAhyɛnsode}}
23.

Can you prove it using the equation? how?

Asemmisa {{asɛmmisaAhyɛnsode}}
24.

A cannonball is fired and you are given the following information

Initial velocity = $4\hat i +7\hat j$ $\frac{m}{s}$, so velocity in the x direction is 4 m/s and y direction is 7m/s
total horizontal distance when it hits the ground = 7 m

acceleration due to gravity = 10 m/s^2

acceleration in the x direction = 0

you are asked how far off the ground the cannonball is fired from.

you would have to use both position AND velocity equations to solve this. Without doing any math, explain what your unknowns are, which equation you would use to find one, and then which equation you might use to find the other.

Asemmisa {{asɛmmisaAhyɛnsode}}
25.

How are you feeling about each of these

  • how to determine what your givens are

  • how to determine what your unknown is

  • how to figure out which equation to use

  • how to use the equations

  • whether or add or subtract vectors

  • Using two equations to solve one problem

  • I've got this

  • I'm fuzzy

  • so confused