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Laabri

Algebra I Chapter 5 Test

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Last updated 20 days ago
22 Nsɛmmisa
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S403

In the following problems, for compound inequalities, join them on one graph. For "or" inequalities (two inequalities going in opposite directions), graph each part of the solution separately. Graph the first inequality in Graph 1 then click on Graph 2 to graph the other.

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1.

If $A = \{1, 2, 3, 4, 5\}$ and $B = \{2, 4, 6\}$, then $A \cup B = $.

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2.

The solution set of $(x - 4)(x + 5) = 0$ is

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3.

Every point on the number line represents

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4.

If $a = 3$ and $b = -4$, which of these inequalities is true?

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5.

${\text{integers}} \cap \{\text{whole numbers}\} = \{0\}$

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6.

If $-3x < 12$, then $x < -4$.

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7.

If $(x, y) = (-3, -8)$, then the ratio of $y$ to $x$ is a number that is greater than $-2$.

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8.

$|5| - |-3| = |5 - 3|$

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9.

If a number is negative, then its opposite is positive.

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10.

Graph the solution of the inequality on the number line.

$-16>-4x$

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
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11.

Graph the solution on the number line.

$18+7x\le-24$

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
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12.

Graph the solution on the number line.

$6x\le12x$

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
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13.

Represent the following inequality in interval notation:

$x\le-4$

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14.

$x(4x+12)=0$

Solve for $x$.

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15.

$|x+8|=12$

Solve for $x$.

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16.

Find the probability that a number selected at random from $\{-2,-1,0,1,2\}$ is a solution of $8x-3<12$

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17.

$x>-5$ and $x<3$

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
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18.

$x \leq -5$ or $x > -2$
Graph here

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
Asemmisa {{asɛmmisaAhyɛnsode}}
19.

$-1 \leq x \leq 5$
Graph here

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
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20.

$|x| \leq 2.5$
Graph the solution on the number line.

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
Asemmisa {{asɛmmisaAhyɛnsode}}
21.

$2x + 12 < 0$ or $-2(x + 2) < 8$

  • Klik Graph tab (Graph 1, Graph 2, ne nea ɛkeka ho) so ma graph biara a ɛsɛ sɛ wobɔ.
  • Klik graph no akyi na fa asɛm bi a wɔato mu ka ho. Klik beae bi a wɔato mu so na dan no baabi a wɔabue. Klik so bio na popa. Fa nsɛntitiriw abien ka ho na ama woanya nkyerɛwde fã bi.
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22.

Wanda bought a box of Plenty Good candy. She found 7 black, 9 white, and 12 pink pieces in the box. How many more pink pieces would have to be in the box for the probability of selecting a pink piece to be $\frac{1}{2}$?